anonymous
  • anonymous
how to I simplify p^(-2/3)/ p^(5/6)?
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
I have the answer for this one -> 1/p^(1/6) but I don't know how to get to that answer...
anonymous
  • anonymous
Subtract the second exponent from the first.
anonymous
  • anonymous
Subtract the exponents.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
that doesn't get me to the right answer...
anonymous
  • anonymous
\[p^{-\frac{2}{3}} / p^{\frac{5}{6}} = p^{-\frac{2}{3} - \frac{5}{6}}\]\[=p^{-\frac{3}{2}} = 1/{p^{\frac{3}{2}}}\] That's what I get.
anonymous
  • anonymous
okay. that's not the right answer but it helped me get it. thanks
anonymous
  • anonymous
Coincidentally, this gives the answer you have.. \[p^\frac{2}{3}/ p^\frac{5}{6}\]
anonymous
  • anonymous
The answer I gave is definitely correct.

Looking for something else?

Not the answer you are looking for? Search for more explanations.