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Mimi_x3
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Amy is 20m S30°W from a tree. Belinda is 50m 110° T from the same tree. Find the distance between them, to the nearest metre.
 3 years ago
 3 years ago
Mimi_x3 Group Title
Amy is 20m S30°W from a tree. Belinda is 50m 110° T from the same tree. Find the distance between them, to the nearest metre.
 3 years ago
 3 years ago

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fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
what do S30°W and 110° T mean ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Um, I'm not sure but i think South 30 degrees West , 110 degrees true bearing idk. I haven't done it in ages so I forgot xD
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315630919336:dw
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
like that ^^^ ?
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315631114054:dw
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Um, idk , it looks right though xDD
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
How can I find the distance between them ?
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315631564224:dw
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Um, I don't think that it requires sin and cos, its bearings
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315631903573:dw
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
What? There's not values of x and y, how can you use the distance formula ?
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
I got the values of x and y using the sin() and cos() in the table I drew above. Rounded to the nearest metre, I get 64 meters distance.
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Okay, tyvm (:
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
does it make sense ? did you learn this stuff in the past ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Not in the past xD, I learnt it year 7 and now I forgot xD But I remember that there's an easier way that doesn't require sin and cos
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
Well , if there is an easier way, I hope someone will post it here  coz I'd like to know it too :)
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Hey, you know your diagram what is the angle degrees thing for AB
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
what do you mean ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
dw:1315632702671:dw
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
yes we can calculate that  it's 240110 = 130 degrees
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
and you're right that we can make the problem simpler
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Yep, there's a formula to calculate it then, was it the sine or cosine formula ? or was it soh cah toa ?
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315633004738:dw
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
dw:1315634036159:dw
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
I would need to calculate to find out  why are you asking ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
If that angle can be found, then I can use the sine rule xD
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
are you trying to use the law of the cosines ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
No, the Sine Rule it says it in my book xD
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
which sine rule ? a/sin(A)=b/sin(B)=c/sin(C) ?
 3 years ago

upsilon Group TitleBest ResponseYou've already chosen the best response.2
Yes, that's it @fiddle
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Yep that xD
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
yes, but we only have one angle , that 130 degrees at this point.
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
I know , but the other angle is 30 right ? the one that I drew
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
why did you pick 30 degrees ?
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
is it becasue sin(30)=1/2 ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Well, the question S30°W so that angle is 30 right ?
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315634688115:dw
 3 years ago

upsilon Group TitleBest ResponseYou've already chosen the best response.2
No, you can't say that...@mimidw:1315634688202:dw
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
The 30 degrees would be relative to the black line I drew.
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
yeah, upsilon says the same thing.
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Can it be 60 then, since 9030 = 60 ?
 3 years ago

upsilon Group TitleBest ResponseYou've already chosen the best response.2
You can't decide like that you need the angle to be in ratio with the opposite sides...
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
but the law of the cosines might work here.
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
http://hyperphysics.phyastr.gsu.edu/hbase/lcos.html
 3 years ago

upsilon Group TitleBest ResponseYou've already chosen the best response.2
Yea, that will work
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
dw:1315635067683:dw
 3 years ago

upsilon Group TitleBest ResponseYou've already chosen the best response.2
\[d = \sqrt{ a^2 + b^2  2*a*b*cos\alpha}\]
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
Okay, tyvm (:
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=sqrt%2820^2%2B50^22*20*50*cos%28130%29%29 It's 64 , same answer I got with the first method :)
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
and it's much shorter than the first method :)
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
yup xD. Your method looked so complicated before (:
 3 years ago
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