anushkaudeshan Group Title cosecx = 2, so what is (cot^2x + 3tan^2x)/8sin^2x - cosec^2x + 6 3 years ago 3 years ago

1. satellite73

$\csc(x)=2\iff \sin(x)=\frac{1}{2}$ gives $\cos(x)=\pm\frac{\sqrt{3}}{2}$ and so $\tan^2(x)=(\frac{1}{2}\times \frac{2}{\sqrt{3}})^2=\frac{1}{3}$ and so on for the rest

2. satellite73

i can work it out if you like.

3. robtobey

$\left(\left.\left(\text{Cot}[x]^2 + 3 \text{ Tan}[x]^2\right)\right/8 \text{ Sin}[x]^2\right)- \text{Csc}[x]^2+ 6$Replace x with the ArcCsc[2] and simplify.$\frac{17}{8}$