Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Mimi_x3

  • 3 years ago

Cindy is some distance NW from a building Don is some distance due North the same building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest one-tenth of metre.

  • This Question is Closed
  1. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You need to use c^2 = a^2 + b^2 in this one, and include sin and cos. You know one is north, and the other is northwest. |dw:1315722352020:dw|

  2. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh the pythagoras theorem ? But then I don't know the other 2 sides whats the point of it then ?

  3. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a*arcsin(45) = 40m

  4. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    whoops..

  5. lakshmandornala
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @ekscentri:- I don't think it is a rectangular triangle.

  6. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    arcsin ? what's that ?

  7. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a*sin(45)=40m

  8. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    try cindy as 56.6m and Don as 113.1m

  9. lakshmandornala
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry right angled triangle

  10. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh I get it tyvm (:

  11. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Was that the right answer?

  12. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Idk, it seems right, I will get the solution to it next week, then I will tell you if its right .

  13. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol, okay. I'm assuming that's how it is, but I could be very wrong.....let's look at it for one more minute.

  14. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1315722861254:dw|

  15. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah, it seems right that the angle is 45 degrees, so I think that its right, not sure though. Thank you for helping anyways (:

  16. Ekscentrix
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no prob. Good luck.

  17. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.