Mimi_x3
  • Mimi_x3
Cindy is some distance NW from a building Don is some distance due North the same building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest one-tenth of metre.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
You need to use c^2 = a^2 + b^2 in this one, and include sin and cos. You know one is north, and the other is northwest. |dw:1315722352020:dw|
Mimi_x3
  • Mimi_x3
Oh the pythagoras theorem ? But then I don't know the other 2 sides whats the point of it then ?
anonymous
  • anonymous
a*arcsin(45) = 40m

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anonymous
  • anonymous
whoops..
anonymous
  • anonymous
@ekscentri:- I don't think it is a rectangular triangle.
Mimi_x3
  • Mimi_x3
arcsin ? what's that ?
anonymous
  • anonymous
a*sin(45)=40m
anonymous
  • anonymous
try cindy as 56.6m and Don as 113.1m
anonymous
  • anonymous
sorry right angled triangle
Mimi_x3
  • Mimi_x3
Oh I get it tyvm (:
anonymous
  • anonymous
Was that the right answer?
Mimi_x3
  • Mimi_x3
Idk, it seems right, I will get the solution to it next week, then I will tell you if its right .
anonymous
  • anonymous
lol, okay. I'm assuming that's how it is, but I could be very wrong.....let's look at it for one more minute.
anonymous
  • anonymous
|dw:1315722861254:dw|
Mimi_x3
  • Mimi_x3
Yeah, it seems right that the angle is 45 degrees, so I think that its right, not sure though. Thank you for helping anyways (:
anonymous
  • anonymous
no prob. Good luck.

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