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Mimi_x3

  • 4 years ago

Cindy is some distance NW from a building Don is some distance due North the same building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest one-tenth of metre.

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  1. Ekscentrix
    • 4 years ago
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    You need to use c^2 = a^2 + b^2 in this one, and include sin and cos. You know one is north, and the other is northwest. |dw:1315722352020:dw|

  2. Mimi_x3
    • 4 years ago
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    Oh the pythagoras theorem ? But then I don't know the other 2 sides whats the point of it then ?

  3. Ekscentrix
    • 4 years ago
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    a*arcsin(45) = 40m

  4. Ekscentrix
    • 4 years ago
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    whoops..

  5. lakshmandornala
    • 4 years ago
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    @ekscentri:- I don't think it is a rectangular triangle.

  6. Mimi_x3
    • 4 years ago
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    arcsin ? what's that ?

  7. Ekscentrix
    • 4 years ago
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    a*sin(45)=40m

  8. Ekscentrix
    • 4 years ago
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    try cindy as 56.6m and Don as 113.1m

  9. lakshmandornala
    • 4 years ago
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    sorry right angled triangle

  10. Mimi_x3
    • 4 years ago
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    Oh I get it tyvm (:

  11. Ekscentrix
    • 4 years ago
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    Was that the right answer?

  12. Mimi_x3
    • 4 years ago
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    Idk, it seems right, I will get the solution to it next week, then I will tell you if its right .

  13. Ekscentrix
    • 4 years ago
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    lol, okay. I'm assuming that's how it is, but I could be very wrong.....let's look at it for one more minute.

  14. Ekscentrix
    • 4 years ago
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    |dw:1315722861254:dw|

  15. Mimi_x3
    • 4 years ago
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    Yeah, it seems right that the angle is 45 degrees, so I think that its right, not sure though. Thank you for helping anyways (:

  16. Ekscentrix
    • 4 years ago
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    no prob. Good luck.

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