Mimi_x3
Cindy is some distance NW from a building Don is some distance due North the same building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest one-tenth of metre.
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Ekscentrix
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You need to use c^2 = a^2 + b^2 in this one, and include sin and cos. You know one is north, and the other is northwest. |dw:1315722352020:dw|
Mimi_x3
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Oh the pythagoras theorem ? But then I don't know the other 2 sides whats the point of it then ?
Ekscentrix
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a*arcsin(45) = 40m
Ekscentrix
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whoops..
lakshmandornala
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@ekscentri:- I don't think it is a rectangular triangle.
Mimi_x3
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arcsin ? what's that ?
Ekscentrix
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a*sin(45)=40m
Ekscentrix
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try cindy as 56.6m and Don as 113.1m
lakshmandornala
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sorry right angled triangle
Mimi_x3
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Oh I get it tyvm (:
Ekscentrix
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Was that the right answer?
Mimi_x3
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Idk, it seems right, I will get the solution to it next week, then I will tell you if its right .
Ekscentrix
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lol, okay. I'm assuming that's how it is, but I could be very wrong.....let's look at it for one more minute.
Ekscentrix
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|dw:1315722861254:dw|
Mimi_x3
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Yeah, it seems right that the angle is 45 degrees, so I think that its right, not sure though.
Thank you for helping anyways (:
Ekscentrix
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no prob. Good luck.