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Mimi_x3 Group Title

Cindy is some distance NW from a building Don is some distance due North the same building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest one-tenth of metre.

  • 2 years ago
  • 2 years ago

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  1. Ekscentrix Group Title
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    You need to use c^2 = a^2 + b^2 in this one, and include sin and cos. You know one is north, and the other is northwest. |dw:1315722352020:dw|

    • 2 years ago
  2. Mimi_x3 Group Title
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    Oh the pythagoras theorem ? But then I don't know the other 2 sides whats the point of it then ?

    • 2 years ago
  3. Ekscentrix Group Title
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    a*arcsin(45) = 40m

    • 2 years ago
  4. Ekscentrix Group Title
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    whoops..

    • 2 years ago
  5. lakshmandornala Group Title
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    @ekscentri:- I don't think it is a rectangular triangle.

    • 2 years ago
  6. Mimi_x3 Group Title
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    arcsin ? what's that ?

    • 2 years ago
  7. Ekscentrix Group Title
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    a*sin(45)=40m

    • 2 years ago
  8. Ekscentrix Group Title
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    try cindy as 56.6m and Don as 113.1m

    • 2 years ago
  9. lakshmandornala Group Title
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    sorry right angled triangle

    • 2 years ago
  10. Mimi_x3 Group Title
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    Oh I get it tyvm (:

    • 2 years ago
  11. Ekscentrix Group Title
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    Was that the right answer?

    • 2 years ago
  12. Mimi_x3 Group Title
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    Idk, it seems right, I will get the solution to it next week, then I will tell you if its right .

    • 2 years ago
  13. Ekscentrix Group Title
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    lol, okay. I'm assuming that's how it is, but I could be very wrong.....let's look at it for one more minute.

    • 2 years ago
  14. Ekscentrix Group Title
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    |dw:1315722861254:dw|

    • 2 years ago
  15. Mimi_x3 Group Title
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    Yeah, it seems right that the angle is 45 degrees, so I think that its right, not sure though. Thank you for helping anyways (:

    • 2 years ago
  16. Ekscentrix Group Title
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    no prob. Good luck.

    • 2 years ago
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