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FreeTrader
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Problem Set 1 Question 1A1 b)
By completing the square, use translation and change of scale to sketch:
y = 3x^2 + 6x +2
Here is the method I attempted, but with a different result than shown in the Solutions. Where am I going wrong?
y = 3x^2 + 6x +2
y  2 = 3x^2 + 6x [move 2 to the left side]
y  2 = 3(x^2 +2x) [factor out 3]
y  2 +1 = 3(x^2 +2x +1) [complete the square]
y  1 = 3(x +1)^2 [rearrange toward slope  intercept form]
y = 3(x+1)^2 +1 [add one to both sides]
Now, I have it in slopeintercept form but my answer is different from the Solution. Help?
 3 years ago
 3 years ago
FreeTrader Group Title
Problem Set 1 Question 1A1 b) By completing the square, use translation and change of scale to sketch: y = 3x^2 + 6x +2 Here is the method I attempted, but with a different result than shown in the Solutions. Where am I going wrong? y = 3x^2 + 6x +2 y  2 = 3x^2 + 6x [move 2 to the left side] y  2 = 3(x^2 +2x) [factor out 3] y  2 +1 = 3(x^2 +2x +1) [complete the square] y  1 = 3(x +1)^2 [rearrange toward slope  intercept form] y = 3(x+1)^2 +1 [add one to both sides] Now, I have it in slopeintercept form but my answer is different from the Solution. Help?
 3 years ago
 3 years ago

This Question is Closed

Throol Group TitleBest ResponseYou've already chosen the best response.1
In your fourth step, you've added 1 to the left side, but 3 to the right (3(+1), so the quantities are no longer equal. Try adding 3 to both sides, and you should get what you're looking for :)
 3 years ago

Throol Group TitleBest ResponseYou've already chosen the best response.1
\[y2=3(x ^{2}+2x)\] Next you'll add 3 to both sides: \[y2+3=3(x ^{2}+2x)+3\] Factor out the 3, \[y+1=3(x ^{2}+2x+1)\] and take it from there.
 3 years ago

FreeTrader Group TitleBest ResponseYou've already chosen the best response.0
Thank you, Throol. I see that your solution is equivalent to the original equation.
 3 years ago
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