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Antwan_Dalski
A football is kicked at an 50 degree angle to the horizontal , travels a horizontal distance of 20m before hitting the ground. what is the initial speed? please tell me how you would do this
Wind resistance is not a factor in this question as we haven't done that yet.
let u be the initial velocity , devide it into two component x and y the angle is 50 degree given so u in x direction = u cos50 in y direction = u sine50 time period = t= (2 u sine50)/g and horizontal distance = u cos50 * t ( acceleration in x direction is zero) by putting the value of t in above eqn yuou will get s=ucos50* (2 u sine50)/g 20 g = 2 u^2 cos50 * sine50 from here u can get the value of u which is initial velocity....