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FreeTrader

Since the derivative of x^-1 is -x^-2, is it correct to then work it further to get the "best answer" as 1/-sqrt x and then rationalize the denominator by multiplying by 1 as in (1/-sqrt x) * (-Sqrt x/-Sqrt X) to get -Sqrt x / x ???

  • 2 years ago
  • 2 years ago

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  1. junwagh
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    that probably depends on your teacher? Rationalizing it is certainly not incorrect.

    • 2 years ago
  2. FreeTrader
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    My instructor counts off for math grammar I never heard of before.

    • 2 years ago
  3. junwagh
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    ask him/her then to be sure. In my class I could leave it as x^-1

    • 2 years ago
  4. FreeTrader
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    This is my first negative exponent in a derivative. Wondering if it needs to be left as it comes out of the rule, or further refined to rationalized denominator form.

    • 2 years ago
  5. FreeTrader
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    I've differentiated TWICE! Yeah!!!

    • 2 years ago
  6. junwagh
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    In my textbook they leave it as a negative exponent, but that might be because of space considerations. Seriously, just ask your teacher.

    • 2 years ago
  7. FreeTrader
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    Thanks!

    • 2 years ago
  8. junwagh
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    and congratulations!!!

    • 2 years ago
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