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marissapaige
It's silly that I've gone years and years and I still don't understand it...but could someone explain distance problems to me?
Please pose a specific distance problem... Such as...?
I don't have an example off the top of my head... but just like, Uhm...say two trains are heading toward each other. One is going 40 MPH and the other is going 25MPH. How long would it take for them to meet?
Distance divided by time=speed. Time times speed=Distance
Insufficient info. So, what you ought to do is find a problem you want to work and post your question. Just knowing the speed won't tell you enough to figure out the time. what else do you need? What if one train is pointed east in SF and the other is pointed West in NYC? or what if one is in Missouri? See?
Oh! I see. Terribly sorry. Let's say, to begin with, they are 170 MPH apart. One heading north, one heading south.
MPH? Sorry- I mean miles.
Try an easier problem. Your car is at home. The grocery store is 10 miles away. If your route is a straight line at constant speed of 10 miles per hour, how long will it take you to travel to the store?
One hour. I understand that, and I understand the formula, but it's when there are two different objects involved. But thank you none-the-less.
Okay, moving on up...
So, with two objects moving you just have two separate parts of the problem just like going to the store.
What if the store was very special, a mobile store in a van. It is also moving toward you and departing at the same time as you, also at 10 MPH. How long till you meet the store on your path?
You got it. Now, you can change the speeds of the objects and figure that out.
See where this is going?
Okay, thank you lots! I do indeed. I just never knew where to begin and how to set it up.
Let's say now that you drive at 20 MPH and the store moves toward you at 10 MPH. When will you meet?
Oh my... Would it be fifteen minutes?
You can get a feel for it by trial and error... You will eventually find the moment of meeting, and you will get it!
try the distance formula that kandybabii gave above to confirm your answer.
hint: use it twice. Once for the store, and once for your car.
And so, once I get the 1/2hour for me and the 1hour for the van, what do I do with them?
Use the formula d/t = s rearrange it to st = d after 15 minutes, you see there's a gap still?
20 MPH x 1/4 hour = 5 miles 10 MPH x 1/4 hour = 2.5 miles. Still 2.5 miles apart. Need more time. Lather rinse and repeat until they meet at the same time, is the way to get the hang of it.
Or rather, adjust the time until the distances sum to 10.
I just don't understand...still. :/
try 17 minutes. Use 17/60 ths hours instead of 1/4. See? and just try until the distances of each add to 10, the original distance apart. 10 has to be covered regardless of who goes fast and who goes slow in order for them to meet. That's the problem, more generally.
Okay. I think my problem is I'm a visual learner...so it's more difficult with math. I think in the morning, I'm going to get my friend to help. In my old math class we used to set up a chart, and I was going to do that, but soon realised I didn't remember where the information went.
20mph * x hours + 10mph * x hours = 10 miles
20x makes a line from point a 10x makes a line from point b change x until they connect in between point a and point b at point M for Meeting Point.
With word problems, you have to peel the story away to be left with numbers and units.
Here's a guy who has a website with tons of them on video, and he's great and trustworthy. http://www.khanacademy.org/video/two-passing-bicycles-word-problem?playlist=Algebra
Yeah, I can tell. So, with that equation, you'd have to insert actual numbers for 'x' before you can multiply and say 20x + 10x = 10 and then 30x = 10 and just get 1/3?
And thank you for the video :)
1/3 hours is 20 minutes.
So, you know how to do distance problems after all. Good Job!