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It's silly that I've gone years and years and I still don't understand it...but could someone explain distance problems to me?
 2 years ago
 2 years ago
It's silly that I've gone years and years and I still don't understand it...but could someone explain distance problems to me?
 2 years ago
 2 years ago

This Question is Closed

FreeTraderBest ResponseYou've already chosen the best response.1
Please pose a specific distance problem... Such as...?
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
I don't have an example off the top of my head... but just like, Uhm...say two trains are heading toward each other. One is going 40 MPH and the other is going 25MPH. How long would it take for them to meet?
 2 years ago

kandybabiiBest ResponseYou've already chosen the best response.0
Distance divided by time=speed. Time times speed=Distance
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Insufficient info. So, what you ought to do is find a problem you want to work and post your question. Just knowing the speed won't tell you enough to figure out the time. what else do you need? What if one train is pointed east in SF and the other is pointed West in NYC? or what if one is in Missouri? See?
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
Oh! I see. Terribly sorry. Let's say, to begin with, they are 170 MPH apart. One heading north, one heading south.
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
MPH? Sorry I mean miles.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Try an easier problem. Your car is at home. The grocery store is 10 miles away. If your route is a straight line at constant speed of 10 miles per hour, how long will it take you to travel to the store?
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
One hour. I understand that, and I understand the formula, but it's when there are two different objects involved. But thank you nonetheless.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Okay, moving on up...
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
So, with two objects moving you just have two separate parts of the problem just like going to the store.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
What if the store was very special, a mobile store in a van. It is also moving toward you and departing at the same time as you, also at 10 MPH. How long till you meet the store on your path?
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
You got it. Now, you can change the speeds of the objects and figure that out.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
See where this is going?
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
Okay, thank you lots! I do indeed. I just never knew where to begin and how to set it up.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Let's say now that you drive at 20 MPH and the store moves toward you at 10 MPH. When will you meet?
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
Oh my... Would it be fifteen minutes?
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
You can get a feel for it by trial and error... You will eventually find the moment of meeting, and you will get it!
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
try the distance formula that kandybabii gave above to confirm your answer.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
hint: use it twice. Once for the store, and once for your car.
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
And so, once I get the 1/2hour for me and the 1hour for the van, what do I do with them?
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Use the formula d/t = s rearrange it to st = d after 15 minutes, you see there's a gap still?
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
20 MPH x 1/4 hour = 5 miles 10 MPH x 1/4 hour = 2.5 miles. Still 2.5 miles apart. Need more time. Lather rinse and repeat until they meet at the same time, is the way to get the hang of it.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Or rather, adjust the time until the distances sum to 10.
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
I just don't understand...still. :/
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
try 17 minutes. Use 17/60 ths hours instead of 1/4. See? and just try until the distances of each add to 10, the original distance apart. 10 has to be covered regardless of who goes fast and who goes slow in order for them to meet. That's the problem, more generally.
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
Okay. I think my problem is I'm a visual learner...so it's more difficult with math. I think in the morning, I'm going to get my friend to help. In my old math class we used to set up a chart, and I was going to do that, but soon realised I didn't remember where the information went.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
20mph * x hours + 10mph * x hours = 10 miles
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
20x makes a line from point a 10x makes a line from point b change x until they connect in between point a and point b at point M for Meeting Point.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
With word problems, you have to peel the story away to be left with numbers and units.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
Here's a guy who has a website with tons of them on video, and he's great and trustworthy. http://www.khanacademy.org/video/twopassingbicycleswordproblem?playlist=Algebra
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
Yeah, I can tell. So, with that equation, you'd have to insert actual numbers for 'x' before you can multiply and say 20x + 10x = 10 and then 30x = 10 and just get 1/3?
 2 years ago

marissapaigeBest ResponseYou've already chosen the best response.1
And thank you for the video :)
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
1/3 hours is 20 minutes.
 2 years ago

FreeTraderBest ResponseYou've already chosen the best response.1
So, you know how to do distance problems after all. Good Job!
 2 years ago
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