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anonymous
 5 years ago
It's silly that I've gone years and years and I still don't understand it...but could someone explain distance problems to me?
anonymous
 5 years ago
It's silly that I've gone years and years and I still don't understand it...but could someone explain distance problems to me?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please pose a specific distance problem... Such as...?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't have an example off the top of my head... but just like, Uhm...say two trains are heading toward each other. One is going 40 MPH and the other is going 25MPH. How long would it take for them to meet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Distance divided by time=speed. Time times speed=Distance

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Insufficient info. So, what you ought to do is find a problem you want to work and post your question. Just knowing the speed won't tell you enough to figure out the time. what else do you need? What if one train is pointed east in SF and the other is pointed West in NYC? or what if one is in Missouri? See?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh! I see. Terribly sorry. Let's say, to begin with, they are 170 MPH apart. One heading north, one heading south.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0MPH? Sorry I mean miles.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Try an easier problem. Your car is at home. The grocery store is 10 miles away. If your route is a straight line at constant speed of 10 miles per hour, how long will it take you to travel to the store?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0One hour. I understand that, and I understand the formula, but it's when there are two different objects involved. But thank you nonetheless.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, moving on up...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, with two objects moving you just have two separate parts of the problem just like going to the store.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What if the store was very special, a mobile store in a van. It is also moving toward you and departing at the same time as you, also at 10 MPH. How long till you meet the store on your path?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You got it. Now, you can change the speeds of the objects and figure that out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0See where this is going?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, thank you lots! I do indeed. I just never knew where to begin and how to set it up.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let's say now that you drive at 20 MPH and the store moves toward you at 10 MPH. When will you meet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh my... Would it be fifteen minutes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can get a feel for it by trial and error... You will eventually find the moment of meeting, and you will get it!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try the distance formula that kandybabii gave above to confirm your answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hint: use it twice. Once for the store, and once for your car.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And so, once I get the 1/2hour for me and the 1hour for the van, what do I do with them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the formula d/t = s rearrange it to st = d after 15 minutes, you see there's a gap still?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.020 MPH x 1/4 hour = 5 miles 10 MPH x 1/4 hour = 2.5 miles. Still 2.5 miles apart. Need more time. Lather rinse and repeat until they meet at the same time, is the way to get the hang of it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or rather, adjust the time until the distances sum to 10.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just don't understand...still. :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try 17 minutes. Use 17/60 ths hours instead of 1/4. See? and just try until the distances of each add to 10, the original distance apart. 10 has to be covered regardless of who goes fast and who goes slow in order for them to meet. That's the problem, more generally.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay. I think my problem is I'm a visual learner...so it's more difficult with math. I think in the morning, I'm going to get my friend to help. In my old math class we used to set up a chart, and I was going to do that, but soon realised I didn't remember where the information went.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.020mph * x hours + 10mph * x hours = 10 miles

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.020x makes a line from point a 10x makes a line from point b change x until they connect in between point a and point b at point M for Meeting Point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0With word problems, you have to peel the story away to be left with numbers and units.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here's a guy who has a website with tons of them on video, and he's great and trustworthy. http://www.khanacademy.org/video/twopassingbicycleswordproblem?playlist=Algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I can tell. So, with that equation, you'd have to insert actual numbers for 'x' before you can multiply and say 20x + 10x = 10 and then 30x = 10 and just get 1/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And thank you for the video :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/3 hours is 20 minutes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, you know how to do distance problems after all. Good Job!
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