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I'm not sure if I enter these in wrong or what.. but are you able to tell me which number goes to which blank?
#1 avg speed=60mph; distance=x, then time=x/60 #2 time=x/40 #3 total driving time=42-25 x can be obtained by solving: x/60+x/40=42-25
I've entered what annand have and it's correct.. but I'm trying to solve for the last problem now. which is solving for x
exactly, suzi... but isn't 42=(travel time from a to b)+ staying time+(ravel time from b to a)
so to solve X, (x/60) + (x/40) = 17 I would have to multiply 60 by each side, correct? and solve?
better multiply both sides with 120... its a multiple of both 40 & 60...
Are you able to show me the steps?
try your hand... if its difficult, i'll help...
17*120 = 2040.. right? then does that make the x/60 + x/40 = to x? since it all cancels out?
after multiplying with 120: 2x+3x=17*120 5x=17*120 x=17*120/5
you don't need to find 17*120 outrightly... 120/5=24
so how did you get 3 and 2?
2x + 3x
Thanks a lot annand! <3
\[120*\left( x/60+x/40 \right)=(120*x/60)+(120*x/40)=2x+3x\]