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Josee Group Title

Find all values of x at which the tangent line to the graph of y =x^2/(x + 3) is horizontal.

  • 3 years ago
  • 3 years ago

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    solve for Min and Max, which means where your first derivative is zero.

    • 3 years ago
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    The tangent line is horizontal where the slope is zero. The slope is zero where the first derivative is zero. Differentiate the equation. Then solve the derivative for values which result in zero. I am in my first week of calculus class, so I don't know how to differentiate something with a x in the denominator yet. But, I am sure I have told you the correct approach.

    • 3 years ago
  3. Josee Group Title
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    you're right. im just like kinda stuck.. i have, after taking the derivative, (2x^3+6x-x^2)/(x+3)

    • 3 years ago
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    so, there is more than one point but like im stuck figuring it out when x=0

    • 3 years ago
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    If you are sure you differentiated right, you could try a graphing calculator, use the y= feature, then graph and solve for zeros.

    • 3 years ago
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    Best wishes. G'nite.

    • 3 years ago
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