Find all values of x at which the tangent line to the graph of y =x^2/(x + 3) is horizontal.

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Find all values of x at which the tangent line to the graph of y =x^2/(x + 3) is horizontal.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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solve for Min and Max, which means where your first derivative is zero.
The tangent line is horizontal where the slope is zero. The slope is zero where the first derivative is zero. Differentiate the equation. Then solve the derivative for values which result in zero. I am in my first week of calculus class, so I don't know how to differentiate something with a x in the denominator yet. But, I am sure I have told you the correct approach.
you're right. im just like kinda stuck.. i have, after taking the derivative, (2x^3+6x-x^2)/(x+3)

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so, there is more than one point but like im stuck figuring it out when x=0
If you are sure you differentiated right, you could try a graphing calculator, use the y= feature, then graph and solve for zeros.
Best wishes. G'nite.

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