Here's the question you clicked on:
Josee
Find all values of x at which the tangent line to the graph of y =x^2/(x + 3) is horizontal.
solve for Min and Max, which means where your first derivative is zero.
The tangent line is horizontal where the slope is zero. The slope is zero where the first derivative is zero. Differentiate the equation. Then solve the derivative for values which result in zero. I am in my first week of calculus class, so I don't know how to differentiate something with a x in the denominator yet. But, I am sure I have told you the correct approach.
you're right. im just like kinda stuck.. i have, after taking the derivative, (2x^3+6x-x^2)/(x+3)
so, there is more than one point but like im stuck figuring it out when x=0
If you are sure you differentiated right, you could try a graphing calculator, use the y= feature, then graph and solve for zeros.
Best wishes. G'nite.