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hermionegranger

  • 3 years ago

Pls Explain motion in a magnetic field ,when velocity is at an angle with the field .

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  1. hermionegranger
    • 3 years ago
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    ??

  2. Ishaan94
    • 3 years ago
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    Okay, Can you tell me the Magnetic Field Force ? I forgot sorry

  3. hermionegranger
    • 3 years ago
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    F = q (V x B )

  4. Ishaan94
    • 3 years ago
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    Hmm Right so do you know cross product ?

  5. hermionegranger
    • 3 years ago
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    i'm a bit confused about it

  6. Ishaan94
    • 3 years ago
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    hmm I won't be able to explain through words but I will try finding some videos fro you. btw do you know about mit ocw ?

  7. hermionegranger
    • 3 years ago
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    nope

  8. hermionegranger
    • 3 years ago
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    what is that?

  9. Ishaan94
    • 3 years ago
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    http://ocw.mit.edu/courses/physics/8-02-electricity-and-magnetism-spring-2002/

  10. hermionegranger
    • 3 years ago
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    oh thanks i'll check it out :)

  11. Ishaan94
    • 3 years ago
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    if you have any doubts please do post them I have to study magnetic field too so your doubts can be helpful to me. sorry If I sound mean

  12. hermionegranger
    • 3 years ago
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    no not at all :) .. i'm going through those videos .. it covers most of my portions ...thank you so much

  13. Ishaan94
    • 3 years ago
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    : ) no problem

  14. hermionegranger
    • 3 years ago
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    |dw:1316022392752:dw| can you tell me how we get v || =\[v \cos \theta\] and v perpendicular = \[v \sin \theta\]

  15. hermionegranger
    • 3 years ago
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    are u here ishaan ?

  16. Ishaan94
    • 3 years ago
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    yea I am ! :D

  17. hermionegranger
    • 3 years ago
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    can you tell me how we get v || =vcosθ and v perpendicular = vsinθ

  18. Ishaan94
    • 3 years ago
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    Okay...I will try |dw:1316022839246:dw|

  19. Ishaan94
    • 3 years ago
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    I think Parallel, Vertical all are taken with respect to x-axis so \(v_{parallel}\) is \(v\cos\theta\)

  20. hermionegranger
    • 3 years ago
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    the angle θ is b/w your vsinθ and v

  21. Ishaan94
    • 3 years ago
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    hmm like this |dw:1316023174038:dw|

  22. hermionegranger
    • 3 years ago
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    yes

  23. Ishaan94
    • 3 years ago
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    Okay ..|dw:1316023222420:dw|

  24. hermionegranger
    • 3 years ago
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    how did u get it ? :(

  25. Ishaan94
    • 3 years ago
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    hmm do you know about sin ratios hmm okay Let me try again \[sin\theta = \frac{Perpendicular }{Hyp}\] so now try to apply this in the triangle the upper triangle

  26. hermionegranger
    • 3 years ago
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    ok let me see..

  27. Ishaan94
    • 3 years ago
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    |dw:1316023483789:dw|

  28. hermionegranger
    • 3 years ago
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    Got It Got It :)

  29. Ishaan94
    • 3 years ago
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    Yay!!

  30. Ishaan94
    • 3 years ago
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    \[\cos\theta =\frac{base}{hyp}\]

  31. hermionegranger
    • 3 years ago
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    thanks a ton :) yea i know it :)

  32. hermionegranger
    • 3 years ago
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    now i'll never forget it :)

  33. Ishaan94
    • 3 years ago
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    !! yay (Again ) :D

  34. hermionegranger
    • 3 years ago
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    ok so vcosθ is Magnetic field and it is given in my notes that thus charge q will hav two motions linear and circular and hence resultant path is helix its axis along direction B |dw:1316023925945:dw|

  35. hermionegranger
    • 3 years ago
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    |dw:1316024026575:dw|

  36. hermionegranger
    • 3 years ago
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    how is it helix ? and how does it have linear and circular motions ?

  37. Ishaan94
    • 3 years ago
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    hmm I think that is where electric field comes to effect

  38. Ishaan94
    • 3 years ago
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    magnetic field makes it to move in circular motion but electric field makes it to move froward

  39. Ishaan94
    • 3 years ago
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    so hence helix is formed

  40. hermionegranger
    • 3 years ago
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    ok thankyou sooooooooooooooooooooooooooooo much for your help yaaayyyy :)

  41. physics.commando
    • 3 years ago
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    Resolve the velocity into two components: one component parallel to the magnetic field; the other component perpendicular to it. The (assumed charged) particle will maintain the velocity that is parallel to the magnetic field, but will simultaneously move in circles in the plane perpendicular to the magnetic field. The combined effect is that it will "spiral" in a helix "following" the magnetic field.

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