hermionegranger
Pls Explain motion in a magnetic field ,when velocity is at an angle with the field .
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hermionegranger
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??
Ishaan94
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Okay, Can you tell me the Magnetic Field Force ? I forgot sorry
hermionegranger
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F = q (V x B )
Ishaan94
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Hmm Right so do you know cross product ?
hermionegranger
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i'm a bit confused about it
Ishaan94
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hmm I won't be able to explain through words but I will try finding some videos fro you.
btw do you know about mit ocw ?
hermionegranger
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nope
hermionegranger
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what is that?
hermionegranger
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oh thanks i'll check it out :)
Ishaan94
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if you have any doubts please do post them I have to study magnetic field too so your doubts can be helpful to me. sorry If I sound mean
hermionegranger
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no not at all :) .. i'm going through those videos .. it covers most of my portions ...thank you so much
Ishaan94
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: ) no problem
hermionegranger
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|dw:1316022392752:dw|
can you tell me how we get
v || =\[v \cos \theta\] and v perpendicular = \[v \sin \theta\]
hermionegranger
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are u here ishaan ?
Ishaan94
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yea I am ! :D
hermionegranger
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can you tell me how we get
v || =vcosθ
and v perpendicular = vsinθ
Ishaan94
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Okay...I will try
|dw:1316022839246:dw|
Ishaan94
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I think Parallel, Vertical all are taken with respect to x-axis so \(v_{parallel}\) is \(v\cos\theta\)
hermionegranger
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the angle θ is b/w your vsinθ and v
Ishaan94
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hmm like this |dw:1316023174038:dw|
hermionegranger
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yes
Ishaan94
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Okay ..|dw:1316023222420:dw|
hermionegranger
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how did u get it ? :(
Ishaan94
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hmm do you know about sin ratios hmm okay Let me try again
\[sin\theta = \frac{Perpendicular }{Hyp}\] so now try to apply this in the triangle the upper triangle
hermionegranger
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ok let me see..
Ishaan94
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|dw:1316023483789:dw|
hermionegranger
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Got It Got It :)
Ishaan94
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Yay!!
Ishaan94
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\[\cos\theta =\frac{base}{hyp}\]
hermionegranger
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thanks a ton :) yea i know it :)
hermionegranger
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now i'll never forget it :)
Ishaan94
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!! yay (Again ) :D
hermionegranger
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ok so vcosθ is Magnetic field and it is given in my notes that thus charge q will hav two motions linear and circular and hence resultant path is helix its axis along direction B |dw:1316023925945:dw|
hermionegranger
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|dw:1316024026575:dw|
hermionegranger
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how is it helix ? and how does it have linear and circular motions ?
Ishaan94
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hmm I think that is where electric field comes to effect
Ishaan94
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magnetic field makes it to move in circular motion but electric field makes it to move froward
Ishaan94
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so hence helix is formed
hermionegranger
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ok thankyou sooooooooooooooooooooooooooooo much for your help yaaayyyy :)
physics.commando
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Resolve the velocity into two components: one component parallel to the magnetic field; the other component perpendicular to it. The (assumed charged) particle will maintain the velocity that is parallel to the magnetic field, but will simultaneously move in circles in the plane perpendicular to the magnetic field. The combined effect is that it will "spiral" in a helix "following" the magnetic field.