Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Pls Explain motion in a magnetic field ,when velocity is at an angle with the field .
 2 years ago
 2 years ago
Pls Explain motion in a magnetic field ,when velocity is at an angle with the field .
 2 years ago
 2 years ago

This Question is Closed

Ishaan94Best ResponseYou've already chosen the best response.2
Okay, Can you tell me the Magnetic Field Force ? I forgot sorry
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
Hmm Right so do you know cross product ?
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
i'm a bit confused about it
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
hmm I won't be able to explain through words but I will try finding some videos fro you. btw do you know about mit ocw ?
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
http://ocw.mit.edu/courses/physics/802electricityandmagnetismspring2002/
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
oh thanks i'll check it out :)
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
if you have any doubts please do post them I have to study magnetic field too so your doubts can be helpful to me. sorry If I sound mean
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
no not at all :) .. i'm going through those videos .. it covers most of my portions ...thank you so much
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
dw:1316022392752:dw can you tell me how we get v  =\[v \cos \theta\] and v perpendicular = \[v \sin \theta\]
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
are u here ishaan ?
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
can you tell me how we get v  =vcosθ and v perpendicular = vsinθ
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
Okay...I will try dw:1316022839246:dw
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
I think Parallel, Vertical all are taken with respect to xaxis so \(v_{parallel}\) is \(v\cos\theta\)
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
the angle θ is b/w your vsinθ and v
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
hmm like this dw:1316023174038:dw
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
Okay ..dw:1316023222420:dw
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
how did u get it ? :(
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
hmm do you know about sin ratios hmm okay Let me try again \[sin\theta = \frac{Perpendicular }{Hyp}\] so now try to apply this in the triangle the upper triangle
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
ok let me see..
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
Got It Got It :)
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
\[\cos\theta =\frac{base}{hyp}\]
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
thanks a ton :) yea i know it :)
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
now i'll never forget it :)
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
ok so vcosθ is Magnetic field and it is given in my notes that thus charge q will hav two motions linear and circular and hence resultant path is helix its axis along direction B dw:1316023925945:dw
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
dw:1316024026575:dw
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
how is it helix ? and how does it have linear and circular motions ?
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
hmm I think that is where electric field comes to effect
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
magnetic field makes it to move in circular motion but electric field makes it to move froward
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.2
so hence helix is formed
 2 years ago

hermionegrangerBest ResponseYou've already chosen the best response.1
ok thankyou sooooooooooooooooooooooooooooo much for your help yaaayyyy :)
 2 years ago

physics.commandoBest ResponseYou've already chosen the best response.0
Resolve the velocity into two components: one component parallel to the magnetic field; the other component perpendicular to it. The (assumed charged) particle will maintain the velocity that is parallel to the magnetic field, but will simultaneously move in circles in the plane perpendicular to the magnetic field. The combined effect is that it will "spiral" in a helix "following" the magnetic field.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.