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hermionegranger

Pls Explain motion in a magnetic field ,when velocity is at an angle with the field .

  • 2 years ago
  • 2 years ago

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  1. hermionegranger
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    ??

    • 2 years ago
  2. Ishaan94
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    Okay, Can you tell me the Magnetic Field Force ? I forgot sorry

    • 2 years ago
  3. hermionegranger
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    F = q (V x B )

    • 2 years ago
  4. Ishaan94
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    Hmm Right so do you know cross product ?

    • 2 years ago
  5. hermionegranger
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    i'm a bit confused about it

    • 2 years ago
  6. Ishaan94
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    hmm I won't be able to explain through words but I will try finding some videos fro you. btw do you know about mit ocw ?

    • 2 years ago
  7. hermionegranger
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    nope

    • 2 years ago
  8. hermionegranger
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    what is that?

    • 2 years ago
  9. Ishaan94
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    http://ocw.mit.edu/courses/physics/8-02-electricity-and-magnetism-spring-2002/

    • 2 years ago
  10. hermionegranger
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    oh thanks i'll check it out :)

    • 2 years ago
  11. Ishaan94
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    if you have any doubts please do post them I have to study magnetic field too so your doubts can be helpful to me. sorry If I sound mean

    • 2 years ago
  12. hermionegranger
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    no not at all :) .. i'm going through those videos .. it covers most of my portions ...thank you so much

    • 2 years ago
  13. Ishaan94
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    : ) no problem

    • 2 years ago
  14. hermionegranger
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    |dw:1316022392752:dw| can you tell me how we get v || =\[v \cos \theta\] and v perpendicular = \[v \sin \theta\]

    • 2 years ago
  15. hermionegranger
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    are u here ishaan ?

    • 2 years ago
  16. Ishaan94
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    yea I am ! :D

    • 2 years ago
  17. hermionegranger
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    can you tell me how we get v || =vcosθ and v perpendicular = vsinθ

    • 2 years ago
  18. Ishaan94
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    Okay...I will try |dw:1316022839246:dw|

    • 2 years ago
  19. Ishaan94
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    I think Parallel, Vertical all are taken with respect to x-axis so \(v_{parallel}\) is \(v\cos\theta\)

    • 2 years ago
  20. hermionegranger
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    the angle θ is b/w your vsinθ and v

    • 2 years ago
  21. Ishaan94
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    hmm like this |dw:1316023174038:dw|

    • 2 years ago
  22. hermionegranger
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    yes

    • 2 years ago
  23. Ishaan94
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    Okay ..|dw:1316023222420:dw|

    • 2 years ago
  24. hermionegranger
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    how did u get it ? :(

    • 2 years ago
  25. Ishaan94
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    hmm do you know about sin ratios hmm okay Let me try again \[sin\theta = \frac{Perpendicular }{Hyp}\] so now try to apply this in the triangle the upper triangle

    • 2 years ago
  26. hermionegranger
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    ok let me see..

    • 2 years ago
  27. Ishaan94
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    |dw:1316023483789:dw|

    • 2 years ago
  28. hermionegranger
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    Got It Got It :)

    • 2 years ago
  29. Ishaan94
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    Yay!!

    • 2 years ago
  30. Ishaan94
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    \[\cos\theta =\frac{base}{hyp}\]

    • 2 years ago
  31. hermionegranger
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    thanks a ton :) yea i know it :)

    • 2 years ago
  32. hermionegranger
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    now i'll never forget it :)

    • 2 years ago
  33. Ishaan94
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    !! yay (Again ) :D

    • 2 years ago
  34. hermionegranger
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    ok so vcosθ is Magnetic field and it is given in my notes that thus charge q will hav two motions linear and circular and hence resultant path is helix its axis along direction B |dw:1316023925945:dw|

    • 2 years ago
  35. hermionegranger
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    |dw:1316024026575:dw|

    • 2 years ago
  36. hermionegranger
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    how is it helix ? and how does it have linear and circular motions ?

    • 2 years ago
  37. Ishaan94
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    hmm I think that is where electric field comes to effect

    • 2 years ago
  38. Ishaan94
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    magnetic field makes it to move in circular motion but electric field makes it to move froward

    • 2 years ago
  39. Ishaan94
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    so hence helix is formed

    • 2 years ago
  40. hermionegranger
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    ok thankyou sooooooooooooooooooooooooooooo much for your help yaaayyyy :)

    • 2 years ago
  41. physics.commando
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    Resolve the velocity into two components: one component parallel to the magnetic field; the other component perpendicular to it. The (assumed charged) particle will maintain the velocity that is parallel to the magnetic field, but will simultaneously move in circles in the plane perpendicular to the magnetic field. The combined effect is that it will "spiral" in a helix "following" the magnetic field.

    • 2 years ago
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