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no it's not a function

If one input has more than one output, its not a function by definition

Exactly because a function is defined as being one to one

not one to one perse; unless im misunderstanding the vernacular

many to one is fine, one to one is invertible; but one to many is not a function

Hmm, I thought I remebered the def being that. Oh well

x^2 is a function, but it is not one to one
(-2)^2 = (2)^2 = 4

Ahh yes you are very much so correct, makes more sense that way :)