anonymous
  • anonymous
is this a function or relation? (3,1), (3,2), (3,3), (3,-2), (3,0)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
no it's not a function
amistre64
  • amistre64
if we define the first components to be inputs; and the second components to be output; then this is not a function
amistre64
  • amistre64
If one input has more than one output, its not a function by definition

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anonymous
  • anonymous
Exactly because a function is defined as being one to one
amistre64
  • amistre64
not one to one perse; unless im misunderstanding the vernacular
amistre64
  • amistre64
many to one is fine, one to one is invertible; but one to many is not a function
anonymous
  • anonymous
Hmm, I thought I remebered the def being that. Oh well
amistre64
  • amistre64
x^2 is a function, but it is not one to one (-2)^2 = (2)^2 = 4
anonymous
  • anonymous
Ahh yes you are very much so correct, makes more sense that way :)

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