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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0if we define the first components to be inputs; and the second components to be output; then this is not a function

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0If one input has more than one output, its not a function by definition

TacoBellMan
 3 years ago
Best ResponseYou've already chosen the best response.0Exactly because a function is defined as being one to one

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0not one to one perse; unless im misunderstanding the vernacular

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0many to one is fine, one to one is invertible; but one to many is not a function

TacoBellMan
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm, I thought I remebered the def being that. Oh well

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0x^2 is a function, but it is not one to one (2)^2 = (2)^2 = 4

TacoBellMan
 3 years ago
Best ResponseYou've already chosen the best response.0Ahh yes you are very much so correct, makes more sense that way :)
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