Here's the question you clicked on:
omarhaps
4x^4-36^2=0
|dw:1316107767915:dw|
\[x=3\sqrt{2}\]
There has to be four solutions
that is one solution gj adequate another solutions is\[x=-3\sqrt{2}\]
we could also find some imaginary solutions by attempting to factor 4x^4-36^2=0 2^2x^4-36^2=0 divide both sides by 2^2 x^4-(36/2)^2=0 x^4-18^2=0 (x^2-18)(x^2+18)=0 x^2-18=0 or x^2+18=0 x^2=18 or x^2=-18 \[x= \pm \sqrt{18}=\pm 3 \sqrt{2} or x=\pm \sqrt{-18}=\pm 3i \sqrt{2}\]
adequate's way is good! \[4x^4=36^2\] take square root of both sides \[2x^2=\pm 36\] divide 2 on both sides \[x^2=\pm 18\] take square root again \[x=\pm \sqrt{\pm 18}\] and you can write the solutions as i have above