A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

AdequateDisclosure
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1316107767915:dw

AdequateDisclosure
 3 years ago
Best ResponseYou've already chosen the best response.3\[x=3\sqrt{2}\]

omarhaps
 3 years ago
Best ResponseYou've already chosen the best response.0There has to be four solutions

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1that is one solution gj adequate another solutions is\[x=3\sqrt{2}\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1we could also find some imaginary solutions by attempting to factor 4x^436^2=0 2^2x^436^2=0 divide both sides by 2^2 x^4(36/2)^2=0 x^418^2=0 (x^218)(x^2+18)=0 x^218=0 or x^2+18=0 x^2=18 or x^2=18 \[x= \pm \sqrt{18}=\pm 3 \sqrt{2} or x=\pm \sqrt{18}=\pm 3i \sqrt{2}\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1adequate's way is good! \[4x^4=36^2\] take square root of both sides \[2x^2=\pm 36\] divide 2 on both sides \[x^2=\pm 18\] take square root again \[x=\pm \sqrt{\pm 18}\] and you can write the solutions as i have above
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.