## anonymous 5 years ago 4x^4-36^2=0

1. anonymous

|dw:1316107767915:dw|

2. anonymous

$x=3\sqrt{2}$

3. anonymous

There has to be four solutions

4. myininaya

that is one solution gj adequate another solutions is$x=-3\sqrt{2}$

5. myininaya

we could also find some imaginary solutions by attempting to factor 4x^4-36^2=0 2^2x^4-36^2=0 divide both sides by 2^2 x^4-(36/2)^2=0 x^4-18^2=0 (x^2-18)(x^2+18)=0 x^2-18=0 or x^2+18=0 x^2=18 or x^2=-18 $x= \pm \sqrt{18}=\pm 3 \sqrt{2} or x=\pm \sqrt{-18}=\pm 3i \sqrt{2}$

6. myininaya

adequate's way is good! $4x^4=36^2$ take square root of both sides $2x^2=\pm 36$ divide 2 on both sides $x^2=\pm 18$ take square root again $x=\pm \sqrt{\pm 18}$ and you can write the solutions as i have above