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omarhaps

  • 4 years ago

4x^4-36^2=0

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  1. AdequateDisclosure
    • 4 years ago
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    |dw:1316107767915:dw|

  2. AdequateDisclosure
    • 4 years ago
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    \[x=3\sqrt{2}\]

  3. omarhaps
    • 4 years ago
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    There has to be four solutions

  4. myininaya
    • 4 years ago
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    that is one solution gj adequate another solutions is\[x=-3\sqrt{2}\]

  5. myininaya
    • 4 years ago
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    we could also find some imaginary solutions by attempting to factor 4x^4-36^2=0 2^2x^4-36^2=0 divide both sides by 2^2 x^4-(36/2)^2=0 x^4-18^2=0 (x^2-18)(x^2+18)=0 x^2-18=0 or x^2+18=0 x^2=18 or x^2=-18 \[x= \pm \sqrt{18}=\pm 3 \sqrt{2} or x=\pm \sqrt{-18}=\pm 3i \sqrt{2}\]

  6. myininaya
    • 4 years ago
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    adequate's way is good! \[4x^4=36^2\] take square root of both sides \[2x^2=\pm 36\] divide 2 on both sides \[x^2=\pm 18\] take square root again \[x=\pm \sqrt{\pm 18}\] and you can write the solutions as i have above

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