yokie
Solve for x
64(x^2) = 25



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lalaly
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\[(8x5)(8x+5)=0\]

imafrenchfri
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divide by 64, square root (25/64)

lalaly
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\[x=\frac{5}{8}\]\[x=\frac{5}{8}\]

Rippythegator
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x^2 =25/64
Square root 25/64 =0.625

yokie
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I'm thinking 5/8

lalaly
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u fractorise it
difference between two squares
(8x5)(8x+5)=0

imafrenchfri
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if you see my above reply, it is \[\sqrt{25/64}\] which leads to \[\pm5/8\]

yokie
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+5/8, 5/8

anushkaudeshan
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64 x^225 = 0
so, x = 5/8 or x = 5/8

anushkaudeshan
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thanks..!!
i am the best..##