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yokie

  • 4 years ago

Solve for x 64(x^2) = 25

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  1. lalaly
    • 4 years ago
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    \[(8x-5)(8x+5)=0\]

  2. imafrenchfri
    • 4 years ago
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    divide by 64, square root (25/64)

  3. lalaly
    • 4 years ago
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    \[x=\frac{5}{8}\]\[x=\frac{-5}{8}\]

  4. Rippythegator
    • 4 years ago
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    x^2 =25/64 Square root 25/64 =0.625

  5. yokie
    • 4 years ago
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    I'm thinking 5/8

  6. lalaly
    • 4 years ago
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    u fractorise it difference between two squares (8x-5)(8x+5)=0

  7. imafrenchfri
    • 4 years ago
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    if you see my above reply, it is \[\sqrt{25/64}\] which leads to \[\pm5/8\]

  8. yokie
    • 4 years ago
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    +5/8, -5/8

  9. anushkaudeshan
    • 4 years ago
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    64 x^2-25 = 0 so, x = -5/8 or x = 5/8

  10. anushkaudeshan
    • 4 years ago
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    thanks..!! i am the best..##

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