Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

kayal

  • 4 years ago

how to solve xy''+2y'+xy=0

  • This Question is Closed
  1. AdequateDisclosure
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you sure this is the given?

  2. nikita2
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.wolframalpha.com/input/?i=xy%27%27%2B2y%27%2Bxy%3D0

  3. nikvist
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[xy''+2y'+xy=0\]\[(xy)'=y+xy'\]\[(xy)''=(y+xy')'=y'+y'+xy''=2y'+xy''\] \[(xy)''+xy=0\quad,\quad z=xy\quad,\quad z''+z=0\]\[z=C_1\cos{x}+C_2\sin{x}\quad\Rightarrow\quad y=\frac{z}{x}=\frac{C_1\cos{x}+C_2\sin{x}}{x}\]

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy