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Mimi_x3
Group Title
Cindy is some distance NW from a building Don is some distance due North of a building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest onetenth of metre.
Can someone please explain step by step on how to do this, I'm like so lost
 3 years ago
 3 years ago
Mimi_x3 Group Title
Cindy is some distance NW from a building Don is some distance due North of a building. If Don is twice as far as Cindy from the building and they are 40m apart, calculate their distances to the building to the nearest onetenth of metre. Can someone please explain step by step on how to do this, I'm like so lost
 3 years ago
 3 years ago

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xactxx Group TitleBest ResponseYou've already chosen the best response.2
Okay. dw:1316163703925:dw
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Do i calculate x by soh cah toa thing ?
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
no, the triangle is not guaranteed to be right angled.
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
do you know of the sine rule?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Yup, do i use the sine rule ?
 3 years ago

MeEngr Group TitleBest ResponseYou've already chosen the best response.0
use law of cosines or law of sines here to find the angles from the lengths
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
you can use cosine rule a^2 = b^2+c^22bc cos A for angle B
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
you'll get x that way
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Okay, like 40/sin45 = x/sinC ?
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
40^2 = x^2 + (2x)^2  2x(2x) cos 45 1600 = x^2 + 4x^2  4x^2 (1/sqrt(2)) 1600 = 5x^2  2sqrt(2)x^2 1600 / (5  2sqrt(2)) = x^2 x^2 = 736.79 x = sqrt(736.79) = 27.14m So Don is 27.1*2 = 54.2m away from the building and Cindy is 27.1m away from the building.
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
btw in the diagram I swapped Cindy and Don, but that's not too much of a problem... the problem works itself out in the same way.
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Um , I did it and I got x= 47.568 xD
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
I still you should still get to the same answer...?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
idk, thats how i did it 1600 = x^2 + 4x^2  4x^2 * cos45 1600 = x^2 *cos45 cos45x^2 = 1600 x^2 = 2262.74 x = 47.578 Did I stuff it up somewhere ?
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
yes. You first perform multiplication, then subtraction, according to BODMAS. You first applied subtraction and then multiplication!
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Hm, i don't follow the BODMAS thing xD Wonder why I stuffed it up xD but how did I stuff it up ? Since I already subtracted it first
 3 years ago

xactxx Group TitleBest ResponseYou've already chosen the best response.2
1600 = x^2 + 4x^2  4x^2 * cos 45 You first performed addition and subtraction: 1600 = x^2 * cos 45 when you should have first performed multiplication! 1600 = x^2 + 4x^2  2.828x^2
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Where did you get 2.828 from ?
 3 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Oh yeah my bad i forgot about that Thank you (:
 3 years ago
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