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An electricity tower is h metres high. The elevation angles of the tower from Aaron and Kevin are respectively 45° and 30° . On the ground, relative to the tower the bearings of Aaron and Kevin are respectively SW and SE. If the boys are 50m apart, find the height h of the tower to the nearest on-tenth of metre. Can someone please explain, I'm so lost xD

Mathematics
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idk
oh
Do i work it out by soh cah toa ?

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Other answers:

I'll try it
Okay, btw I asked the question before and someone drew a different diagram to yours xD
really?
this problem is 3 dimensional|dw:1316171303379:dw|
you are right.
Is it 3D ?
from first two diagrams we get AT = h and KT = \[h \sqrt{3}\] so from 3rd figure AT2 + KT2 = 2500 so on simplifying h = 25 m
the first 2 diagrams are 2 dimensional and the 3rd figure is an overhead view
ohh I get it tyvm (:
|dw:1316171761134:dw| Is this right as well ?>
but the two lines below are inclined at 90 degrees to each other in the 3rd dimension
So its wrong ?
the figure is somewhat like .... try cutting a pyramid with a square base from one corner of base to it's opposite corner symmetrically. then u get a figure similar to what we need (not exactly similar but good enough to understand the above problem)
So the figure I drew was wrong ?:
|dw:1316172253129:dw|
oh 3D trig ?
the above figure is possible only in 3d
it can be in 3D ?
no no u don't need 3d trig. just consider each triangle at one time to get the required variables
Okay, but is it necessary though to draw it ?
the whole point is to test whether u can imagine the required diagram once u get the diagram it is easy simplification. u can see that i used the first two diagrams to get the values of AT and KT in terms of h and then used pythagoras theorem in the final triangle. drawing the diagram is important unless u can visualize it exactly to solve the problem in ur head
Okay tyvm (:

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