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buffon
 3 years ago
Prove This Equation using Boolean Algebra multiplication?
WY + W*YZ* + WXZ + W*XY* = WY + X*YZ* + XY*Z + W*XZ*
Where the variable (or signal) in which i put the asterisk ('*') after is the Complement ... sorry , i can't write the Complement sign here (e.g Bar)
buffon
 3 years ago
Prove This Equation using Boolean Algebra multiplication? WY + W*YZ* + WXZ + W*XY* = WY + X*YZ* + XY*Z + W*XZ* Where the variable (or signal) in which i put the asterisk ('*') after is the Complement ... sorry , i can't write the Complement sign here (e.g Bar)

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pradeepbn
 3 years ago
Best ResponseYou've already chosen the best response.1I Created 2 karnaugh maps to confirm both are same.(Attached).This is one of the ways to do this problem

lyongking
 3 years ago
Best ResponseYou've already chosen the best response.0try applying De Morgan's Law
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