Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A student wishes to dilute 50ml of a solution 0f 0.10 mol L^-1 calcium chloride to obtain ion concentrate of 0.02 mol L^-1. What is the volume of the diltuted solution ? Can someone pls explain step by step (:

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

\[\frac{mol}{L}=M\] You can use the following formula to answer this: \[M_1V_1=M_2V_2\] Note that V is handled in terms of L so we times the 50ml by 10^{-3}. \[0.10M*50(10^{-3})L=0.02M*V_2\] We need to solve for V_2 so we will divide both sides by 0.02. \[\frac{0.10M*50(10^{-3})L}{0.02M}=V_2\] Notice that the M cancel and we are left with L which is what we are seeking. \[0.25L=V_2\] This can also be written as: \[V_2=250ml\] Now if you approach this logically, we're looking to dilute a concentration because the Molarity is going down. The implication here is that we have to add more water so our volume will go up. Note that we have a larger volume for V_2 than V_1.
wow~ ty Osirisis (:
Happy to help. It lets me practice what I learned over the summer :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

lols okay (:

Not the answer you are looking for?

Search for more explanations.

Ask your own question