anonymous
  • anonymous
need help with the attachment
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
a) Just plug in 1 for the numerator and g(x) for the denominator in the quotient rule. b) \[ -{\frac {1+k{{\rm e}^{s}}}{ \left( s+k{{\rm e}^{s}} \right) ^{2}}} \] assuming y is a function of s. c) Follows from \[ x^{-n} = \frac{1}{x^n} \] and \[ \frac{d}{dx} x^n = nx^{n-1} \]
anonymous
  • anonymous
is the quotient rule the same thing as the reciprocal part b?

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anonymous
  • anonymous
What do you mean? The reciprocal rule is a special case of the quotient rule. You can use either one for part b, but it's easier to use the reciprocal rule.
anonymous
  • anonymous
The quotient rule f'g-fg'/g^(2)
anonymous
  • anonymous
but g(x) is just a variable
anonymous
  • anonymous
ok I got it
anonymous
  • anonymous
What is your question? g is not just a variable, it's a function.
anonymous
  • anonymous
Ok, hit good answer.
anonymous
  • anonymous
OK I need help with differentiating the bottom on part could you show me step by step how to differentiate that one?
anonymous
  • anonymous
part b
anonymous
  • anonymous
and also the numerator of the function
anonymous
  • anonymous
You need to differentiate\[ \Large s+k\cdot e^s \] with respect to s.
anonymous
  • anonymous
The derivative of a sum is the sum of derivatives, so differentiate s and then differentiate k*e^s.
anonymous
  • anonymous
What is the derivative of s?
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
1
anonymous
  • anonymous
Yes. And what is the derivative of e^s ?
anonymous
  • anonymous
@ta, see the attachee
anonymous
  • anonymous
e^(s)
anonymous
  • anonymous
Your attachment doesn't include part b) explanation, thats what he asked about.
anonymous
  • anonymous
Yes, so now you can add them together and you get the derivative
anonymous
  • anonymous
And then just plug that into the formula in part a)
anonymous
  • anonymous
1+e^(s)
anonymous
  • anonymous
No! Don't forget the factor k!
anonymous
  • anonymous
k does not depend on s, so you can just leave it unchanged
anonymous
  • anonymous
But you must not forget it :D
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
here u r
anonymous
  • anonymous
raheen there is still no explanation of part b :D
anonymous
  • anonymous
been answered all
anonymous
  • anonymous
part b asking to find using the rule only
anonymous
  • anonymous
ta123 do you have more questions?
anonymous
  • anonymous
whears the other 2 parts are to prove
anonymous
  • anonymous
@ta got that?
anonymous
  • anonymous
lol raheen are you just trying to get a medal, because I can give you one if thats what you want :D
anonymous
  • anonymous
your answer is wrong raheen, I got -1-ke^(s)/(s+ke^(s))^2
anonymous
  • anonymous
no YThe, I always try to help , pls don read the things in wrong way
anonymous
  • anonymous
Your answer is correct ta.
anonymous
  • anonymous
yes, thanks for the help Y and raheen
anonymous
  • anonymous
ta why some ppl are using an offensive words?
anonymous
  • anonymous
I think I stayed with u b4 more than 2 hrs, without any annyance, right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
thank u.
anonymous
  • anonymous
no prob!

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