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anonymous
 4 years ago
need help with the attachment
anonymous
 4 years ago
need help with the attachment

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a) Just plug in 1 for the numerator and g(x) for the denominator in the quotient rule. b) \[ {\frac {1+k{{\rm e}^{s}}}{ \left( s+k{{\rm e}^{s}} \right) ^{2}}} \] assuming y is a function of s. c) Follows from \[ x^{n} = \frac{1}{x^n} \] and \[ \frac{d}{dx} x^n = nx^{n1} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the quotient rule the same thing as the reciprocal part b?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What do you mean? The reciprocal rule is a special case of the quotient rule. You can use either one for part b, but it's easier to use the reciprocal rule.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The quotient rule f'gfg'/g^(2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but g(x) is just a variable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is your question? g is not just a variable, it's a function.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK I need help with differentiating the bottom on part could you show me step by step how to differentiate that one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and also the numerator of the function

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You need to differentiate\[ \Large s+k\cdot e^s \] with respect to s.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The derivative of a sum is the sum of derivatives, so differentiate s and then differentiate k*e^s.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is the derivative of s?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. And what is the derivative of e^s ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ta, see the attachee

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your attachment doesn't include part b) explanation, thats what he asked about.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, so now you can add them together and you get the derivative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And then just plug that into the formula in part a)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No! Don't forget the factor k!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k does not depend on s, so you can just leave it unchanged

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But you must not forget it :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0raheen there is still no explanation of part b :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0part b asking to find using the rule only

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ta123 do you have more questions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whears the other 2 parts are to prove

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol raheen are you just trying to get a medal, because I can give you one if thats what you want :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your answer is wrong raheen, I got 1ke^(s)/(s+ke^(s))^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no YThe, I always try to help , pls don read the things in wrong way

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your answer is correct ta.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, thanks for the help Y and raheen

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ta why some ppl are using an offensive words?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think I stayed with u b4 more than 2 hrs, without any annyance, right?
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