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YTheManifoldBest ResponseYou've already chosen the best response.0
a) Just plug in 1 for the numerator and g(x) for the denominator in the quotient rule. b) \[ {\frac {1+k{{\rm e}^{s}}}{ \left( s+k{{\rm e}^{s}} \right) ^{2}}} \] assuming y is a function of s. c) Follows from \[ x^{n} = \frac{1}{x^n} \] and \[ \frac{d}{dx} x^n = nx^{n1} \]
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
is the quotient rule the same thing as the reciprocal part b?
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
What do you mean? The reciprocal rule is a special case of the quotient rule. You can use either one for part b, but it's easier to use the reciprocal rule.
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
The quotient rule f'gfg'/g^(2)
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
but g(x) is just a variable
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
What is your question? g is not just a variable, it's a function.
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
Ok, hit good answer.
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
OK I need help with differentiating the bottom on part could you show me step by step how to differentiate that one?
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
and also the numerator of the function
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
You need to differentiate\[ \Large s+k\cdot e^s \] with respect to s.
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
The derivative of a sum is the sum of derivatives, so differentiate s and then differentiate k*e^s.
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
What is the derivative of s?
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
Yes. And what is the derivative of e^s ?
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
Your attachment doesn't include part b) explanation, thats what he asked about.
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
Yes, so now you can add them together and you get the derivative
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
And then just plug that into the formula in part a)
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
No! Don't forget the factor k!
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
k does not depend on s, so you can just leave it unchanged
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
But you must not forget it :D
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
raheen there is still no explanation of part b :D
 2 years ago

raheenBest ResponseYou've already chosen the best response.2
part b asking to find using the rule only
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
ta123 do you have more questions?
 2 years ago

raheenBest ResponseYou've already chosen the best response.2
whears the other 2 parts are to prove
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
lol raheen are you just trying to get a medal, because I can give you one if thats what you want :D
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
your answer is wrong raheen, I got 1ke^(s)/(s+ke^(s))^2
 2 years ago

raheenBest ResponseYou've already chosen the best response.2
no YThe, I always try to help , pls don read the things in wrong way
 2 years ago

YTheManifoldBest ResponseYou've already chosen the best response.0
Your answer is correct ta.
 2 years ago

ta123Best ResponseYou've already chosen the best response.1
yes, thanks for the help Y and raheen
 2 years ago

raheenBest ResponseYou've already chosen the best response.2
ta why some ppl are using an offensive words?
 2 years ago

raheenBest ResponseYou've already chosen the best response.2
I think I stayed with u b4 more than 2 hrs, without any annyance, right?
 2 years ago
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