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nilankshi Group TitleBest ResponseYou've already chosen the best response.2
sorry , i don't know
 3 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i hav a question can u help?
 3 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.4
ya sure so on writing ur question!!1
 3 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
n3^(2n+2)8n9 is divisible by 8.Prove
 3 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.4
is ur question correct!!!!1
 3 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
3^(2n+2)8n9 is divisible by 8.Prove
 3 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
............
 3 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.4
let p(n)=n3^(2n+2)8n9 =8m (let m be any value) checking for p(1), lhs: p(1)= 3^(2+2) 89=8117=64=8x8=8m =rhs therefore p(1)is true assume p(k)is true . =>3^(2k+2)8k9=8m \[=>3^{(2k)} = \frac{8m+8k+9}{3^{2}}\](1) to prove :p(k+1)is true substitute k+1 in n in the given eq \[=>3^{2k+4}8(k+1)9= 3^{2k}.3^{4}8k17\]substitute (1) instead of 3^(2k) =>72m+64k+64= =>8(9m+8k+8) therefore p(k+1) is true by principal of mathematical induction , p(n) is true for all n belonging to natural numbers
 3 years ago
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