Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I am a little confused on how to solve this, could someone help me out? A cement block accidentally falls from rest from the ledge of a 73.2-m-high building. When the block is 17.0 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Here initial vel, u=0 as it falls from rest accl, a=-g=-9.8 So \[S=u*t+0.5*a*t^2\] becomes \[S=-0.5*9.8*t^2\]
Time to reach 17m, t1: Here displacement, S=17-73.2 t=t1 Substitute in the above eqn and find t1...
Time to reach 1.7m, t2: S=1.7-73.2 ; t=t2 find t2....

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Time of travel from 17m to 1.7 m= t2-t1 He must evade before this time to save himself...

Not the answer you are looking for?

Search for more explanations.

Ask your own question