I am a little confused on how to solve this, could someone help me out? A cement block accidentally falls from rest from the ledge of a 73.2-m-high building. When the block is 17.0 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?

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Time to reach 17m, t1:
Here displacement, S=17-73.2
t=t1
Substitute in the above eqn and find t1...

Time to reach 1.7m, t2:
S=1.7-73.2 ; t=t2
find t2....

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