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anonymous
 4 years ago
I am a little confused on how to solve this, could someone help me out? A cement block accidentally falls from rest from the ledge of a 73.2mhigh building. When the block is 17.0 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?
anonymous
 4 years ago
I am a little confused on how to solve this, could someone help me out? A cement block accidentally falls from rest from the ledge of a 73.2mhigh building. When the block is 17.0 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here initial vel, u=0 as it falls from rest accl, a=g=9.8 So \[S=u*t+0.5*a*t^2\] becomes \[S=0.5*9.8*t^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Time to reach 17m, t1: Here displacement, S=1773.2 t=t1 Substitute in the above eqn and find t1...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Time to reach 1.7m, t2: S=1.773.2 ; t=t2 find t2....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Time of travel from 17m to 1.7 m= t2t1 He must evade before this time to save himself...
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