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it's equal to 2x+y , eliminate the x's ?

oh that's different than the first one

I think there is a way to do it, but I am not sure how I can get them to all cancel out.

\[((x+y)2−y2)/y \]
goal is to eliminate the x's and be left with only y's to deal with...

BRB

is this part of a LIM problem ?

Yes, how on earth did you guess?

I mean are you looking for:
\[\lim_{y \rightarrow 0} \frac{(x+y)^2-x^2}{y}\]

Uh, indeed I am...

Can you help me get unstuck? I really want to learn how to do this...

\[\lim_{y \rightarrow 0} \frac{\cancel{x^2}+2xy+y^2-\cancel{x^2}}{y}=\lim_{y \rightarrow 0}2x+y=2x\]

Is it acceptable to have a variable in the lim solution?

yes, coz it's basically the derivative:
\[(x^2)'=2x\]

Or is this DNE?!?

the final answer is 2x
which is the derivative of x^2

how was the problem worded ?

So the lim is really 2x?!?

The lim stmt you wrote, preceded by the word "Evaluate:"

yes, so the answer would be 2x

We haven't covered derivatives yet - not until tomorrow. So this is kinda tricky!

this is how they introduce you to derivatives

Are you a student or faculty?

that formula is basically calculating rise over run (where they make the run smaller and smaller)

Ahhhh

neither. I studied math about 20 years ago.

What do you do now that allows you to stay fresh on it? I am 44, BTW.

Well, thank you for your help. I am now a fan.

I want to build up a community on MIT OCW SCHOLAR SVC.

Thanks. Over and out on this case. I had solved it and didn't realize I was done.

It is wonderful. I hope you find time to give it a try during your "me time."

I'm going to resume my homework. I have about a zillion more to go...

OK :)