## anonymous 5 years ago Calculate the wavelength of the radiation released when an electron moves from n=5 to n=2

1. anonymous

$1/\lambda = R ( 1/na ^{2} -1/nb ^{2})$ $R = 1.097 \times 10^{7}$ $1/\lambda = R (1/(2)^{2}-1/(5)^{2})$ $1/\lambda = R (99/25)$ $\lambda = 25/99R$

2. anonymous

thank you!