Here's the question you clicked on:
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Match: 1. Segment TQ bisects ∠RTS; ∠R = ∠S 2. ∠1 = ∠2 3. TQ = TQ 4. Triangle RTQ congruent to Triangle STQ 5. ∠3 = ∠4 6. Segment TQ ⊥ Segment RS a. AAS B. Reflexive C. Definition of perpendicular. D. Given E. Definition of angle bisector F. CPCTE
do you have the triangles or we have to draw them?
oh much better..thank you! :D
ok, lets do it in another way.. do you have any answers? okay yes for 3 its b! :)
i'm completely clueless at this
|dw:1316541042643:dw| bisects <RTS <R=<S Prove: |dw:1316541148988:dw| This is all it says
yes i know it's hard a bit! :( and CCCOONNFFFUUSSIIINNGGGG!!!!! (lol sorry for saying that i know im suppose to say the opposite..) yes well they actually gave you the steps all you have to do is match right? so for 1. Segment TQ bisects ∠RTS; ∠R = ∠S we got E.why? because, (you know that the angle bisector is a ray that separates an angle into to equal adjacent angle) so here is what segment TQ is doing its bisects <RTS which makes <R=<S so the reason is" definition of angle bisector " do you get it? :)