## ][Scene_Queen][ 4 years ago Match: 1. Segment TQ bisects ∠RTS; ∠R = ∠S 2. ∠1 = ∠2 3. TQ = TQ 4. Triangle RTQ congruent to Triangle STQ 5. ∠3 = ∠4 6. Segment TQ ⊥ Segment RS a. AAS B. Reflexive C. Definition of perpendicular. D. Given E. Definition of angle bisector F. CPCTE

1. ][Scene_Queen][

2. aroub

do you have the triangles or we have to draw them?

3. ][Scene_Queen][
4. aroub

oh much better..thank you! :D

5. ][Scene_Queen][

6. aroub

1.E

7. ][Scene_Queen][

would 3 be B?

8. aroub

ok, lets do it in another way.. do you have any answers? okay yes for 3 its b! :)

9. ][Scene_Queen][

i'm completely clueless at this

10. ][Scene_Queen][

|dw:1316541042643:dw| bisects <RTS <R=<S Prove: |dw:1316541148988:dw| This is all it says

11. aroub

yes i know it's hard a bit! :( and CCCOONNFFFUUSSIIINNGGGG!!!!! (lol sorry for saying that i know im suppose to say the opposite..) yes well they actually gave you the steps all you have to do is match right? so for 1. Segment TQ bisects ∠RTS; ∠R = ∠S we got E.why? because, (you know that the angle bisector is a ray that separates an angle into to equal adjacent angle) so here is what segment TQ is doing its bisects <RTS which makes <R=<S so the reason is" definition of angle bisector " do you get it? :)

12. ][Scene_Queen][

no