## allyza_obico 4 years ago by foil method: (2m-5n) (3n-7n)

1. Mimi_x3

6mn - 14mn - 15n^2 + 35n^2 6mn - 14mn +20n^2

2. allyza_obico

3. Mimi_x3

4. allyza_obico

yes

5. Mimi_x3

but there's only one answer to this question

6. allyza_obico

by horizontal method: (2m-5n) (3m-7n)

7. Mimi_x3

oh horizontal method!? I dont know what a horizontal method sorry

8. fiddlearound
9. Mimi_x3

is horizontal method like foil method ?

10. fiddlearound

(sm-5n)(3m-7n) =(2m-5n)3m - (2m-5n)7n and so on ...

11. allyza_obico

12. Mimi_x3

oh but you would get the same answer anyway

13. fiddlearound

you would, if you didn't mess up :) (2m-5n)(2m-7n) =(2m-5n)3m - (2m-5n)7n =6m^2-15mn - 14mn+35n^2 =6m^2 -29mn +35n^2

14. fiddlearound

which I do a lot ...

15. Mimi_x3

looks complicated , the foil method is better xD

16. fiddlearound

I like box method best !!

17. Mimi_x3

what's box method ?

18. fiddlearound

|dw:1316601780696:dw|

19. fiddlearound

|dw:1316601826720:dw|

20. Mimi_x3

wow~ looks more complicated though, first time seeing that method xD

21. fiddlearound

|dw:1316601875640:dw|

22. fiddlearound

it's cool, especially when you multiply stuff like: (2m-5n+8k)(4m+6) How would you do that with FOIL ? :)

23. Mimi_x3

yeah true but you can still do that with FOIL, and the box one looks complicated

24. fiddlearound

it looks that way, until you do a couple of them :)

25. fiddlearound

but it's really all the same

26. Mimi_x3

Yeah might try it some day xD