anonymous
  • anonymous
If you throw a dice 6 times, what's the chance that you'd get a six on: a: exactly one of the throws. b: one or more of the throws.
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

amistre64
  • amistre64
thats a pretty big sample space :)
anonymous
  • anonymous
? I don't understand what your saying... lol
amistre64
  • amistre64
1 6 15 20 15 6 1 neither do i yet :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
a. (1/6)*(5/6)^5*6 = (5/6)^5 b. (5/6)^6
anonymous
  • anonymous
LOL! I was a fool in my math class so I had extra homework... ( threw an apple at the teacher)
anonymous
  • anonymous
er, b. 1-(5/6)^6
amistre64
  • amistre64
P(6 a / a / a / a / a / ) = P(6)*P(\)^5, where / means not a 6
amistre64
  • amistre64
P(6) = 1/6; P(/) = 5/6
anonymous
  • anonymous
Thanks!
amistre64
  • amistre64
satellite is good at these, he does them instead of the crosswords during breakfast :)
anonymous
  • anonymous
exactly one: \[\dbinom{6}{1}\frac{1}{6}\times (\frac{5}{6})^5\]
amistre64
  • amistre64
he has rooms filled with unthrown dice just waiting to be explored lol
anonymous
  • anonymous
they are thrown.
anonymous
  • anonymous
since 6 choose 1 is 6, this answer is really \[(\frac{5}{6})^5\]
anonymous
  • anonymous
Dang! I didn't think I would get so much attention :P
anonymous
  • anonymous
one or more throws means not no sixes. the probability you get no sixes is \[(\frac{5}{6})^6\] so your answer is \[1-(\frac{5}{6})^6\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.