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- anonymous

If you throw a dice 6 times, what's the chance that you'd get a six on:
a: exactly one of the throws.
b: one or more of the throws.

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- anonymous

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- amistre64

thats a pretty big sample space :)

- anonymous

? I don't understand what your saying... lol

- amistre64

1 6 15 20 15 6 1
neither do i yet :)

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- anonymous

a. (1/6)*(5/6)^5*6 = (5/6)^5
b. (5/6)^6

- anonymous

LOL! I was a fool in my math class so I had extra homework... ( threw an apple at the teacher)

- anonymous

er, b. 1-(5/6)^6

- amistre64

P(6 a / a / a / a / a / ) = P(6)*P(\)^5, where / means not a 6

- amistre64

P(6) = 1/6; P(/) = 5/6

- anonymous

Thanks!

- amistre64

satellite is good at these, he does them instead of the crosswords during breakfast :)

- anonymous

exactly one:
\[\dbinom{6}{1}\frac{1}{6}\times (\frac{5}{6})^5\]

- amistre64

he has rooms filled with unthrown dice just waiting to be explored lol

- anonymous

they are thrown.

- anonymous

since 6 choose 1 is 6, this answer is really
\[(\frac{5}{6})^5\]

- anonymous

Dang! I didn't think I would get so much attention :P

- anonymous

one or more throws means not no sixes. the probability you get no sixes is
\[(\frac{5}{6})^6\] so your answer is
\[1-(\frac{5}{6})^6\]

- anonymous

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