## agbyoung Group Title If you throw a dice 6 times, what's the chance that you'd get a six on: a: exactly one of the throws. b: one or more of the throws. 2 years ago 2 years ago

1. amistre64 Group Title

thats a pretty big sample space :)

2. agbyoung Group Title

? I don't understand what your saying... lol

3. amistre64 Group Title

1 6 15 20 15 6 1 neither do i yet :)

4. dimbeni Group Title

a. (1/6)*(5/6)^5*6 = (5/6)^5 b. (5/6)^6

5. agbyoung Group Title

LOL! I was a fool in my math class so I had extra homework... ( threw an apple at the teacher)

6. dimbeni Group Title

er, b. 1-(5/6)^6

7. amistre64 Group Title

P(6 a / a / a / a / a / ) = P(6)*P(\)^5, where / means not a 6

8. amistre64 Group Title

P(6) = 1/6; P(/) = 5/6

9. agbyoung Group Title

Thanks!

10. amistre64 Group Title

satellite is good at these, he does them instead of the crosswords during breakfast :)

11. satellite73 Group Title

exactly one: $\dbinom{6}{1}\frac{1}{6}\times (\frac{5}{6})^5$

12. amistre64 Group Title

he has rooms filled with unthrown dice just waiting to be explored lol

13. satellite73 Group Title

they are thrown.

14. satellite73 Group Title

since 6 choose 1 is 6, this answer is really $(\frac{5}{6})^5$

15. agbyoung Group Title

Dang! I didn't think I would get so much attention :P

16. satellite73 Group Title

one or more throws means not no sixes. the probability you get no sixes is $(\frac{5}{6})^6$ so your answer is $1-(\frac{5}{6})^6$

17. agbyoung Group Title