Here's the question you clicked on:
agbyoung
If you throw a dice 6 times, what's the chance that you'd get a six on: a: exactly one of the throws. b: one or more of the throws.
thats a pretty big sample space :)
? I don't understand what your saying... lol
1 6 15 20 15 6 1 neither do i yet :)
a. (1/6)*(5/6)^5*6 = (5/6)^5 b. (5/6)^6
LOL! I was a fool in my math class so I had extra homework... ( threw an apple at the teacher)
P(6 a / a / a / a / a / ) = P(6)*P(\)^5, where / means not a 6
P(6) = 1/6; P(/) = 5/6
satellite is good at these, he does them instead of the crosswords during breakfast :)
exactly one: \[\dbinom{6}{1}\frac{1}{6}\times (\frac{5}{6})^5\]
he has rooms filled with unthrown dice just waiting to be explored lol
since 6 choose 1 is 6, this answer is really \[(\frac{5}{6})^5\]
Dang! I didn't think I would get so much attention :P
one or more throws means not no sixes. the probability you get no sixes is \[(\frac{5}{6})^6\] so your answer is \[1-(\frac{5}{6})^6\]
Do my other question please: http://openstudy.com/groups/mathematics/updates/4e7a829b0b8b2cb239c38801#/groups/mathematics/updates/4e7a87380b8b2cb239c3ad98