## anonymous 4 years ago If you throw a dice 6 times, what's the chance that you'd get a six on: a: exactly one of the throws. b: one or more of the throws.

1. amistre64

thats a pretty big sample space :)

2. anonymous

? I don't understand what your saying... lol

3. amistre64

1 6 15 20 15 6 1 neither do i yet :)

4. anonymous

a. (1/6)*(5/6)^5*6 = (5/6)^5 b. (5/6)^6

5. anonymous

LOL! I was a fool in my math class so I had extra homework... ( threw an apple at the teacher)

6. anonymous

er, b. 1-(5/6)^6

7. amistre64

P(6 a / a / a / a / a / ) = P(6)*P(\)^5, where / means not a 6

8. amistre64

P(6) = 1/6; P(/) = 5/6

9. anonymous

Thanks!

10. amistre64

satellite is good at these, he does them instead of the crosswords during breakfast :)

11. anonymous

exactly one: $\dbinom{6}{1}\frac{1}{6}\times (\frac{5}{6})^5$

12. amistre64

he has rooms filled with unthrown dice just waiting to be explored lol

13. anonymous

they are thrown.

14. anonymous

since 6 choose 1 is 6, this answer is really $(\frac{5}{6})^5$

15. anonymous

Dang! I didn't think I would get so much attention :P

16. anonymous

one or more throws means not no sixes. the probability you get no sixes is $(\frac{5}{6})^6$ so your answer is $1-(\frac{5}{6})^6$

17. anonymous

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