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101Ryan101

  • 3 years ago

What is the equation to the plane through P(4,-2,3) and parallel to 3x-7z=12

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  1. 101Ryan101
    • 3 years ago
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    I guess just a quick run though of any ideas how to get there in english would help... Any help helps!

  2. 101Ryan101
    • 3 years ago
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    I get the normal vector <3,0,7> and know it runs perpendicular to the plane...

  3. 101Ryan101
    • 3 years ago
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    I can use the point to make a parametric equation... x=4+3t y=-2 z=3+7t

  4. amistre64
    • 3 years ago
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    parallel to a y=0 plane eh ...

  5. amistre64
    • 3 years ago
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    3x - 7z = 12 <3,0,-7> is the normal to this "plane" so its good for the normal for any plane parallel to it right?

  6. amistre64
    • 3 years ago
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    given a normal and a point, all we do is put them together to get the plane equation. 3(x-4)+0(y--2)-7(z-3)=0 3x -12 -7z +21 = 0 3x -7z +9 = 0 should do it

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