## anonymous 4 years ago Find the distance between the two points (5,-3) and (-1,-6) and the midpoint of the line segment that joins the two points.

1. anonymous

$y _{2}-y_{1}/x _{2}-x_{1}$

2. anonymous

plug your points into that question

3. anonymous

that is your slope matt.... distance would be $\sqrt{(x _2-x _1)^2+(y _2-y _1)^2}$

4. anonymous

mid point will be $(\frac{x _1+x _2}{2},\frac{y _1+y _2}{2})$

5. anonymous

thank you very much.

6. anonymous

so your midpont would be $\frac{5+-1}{2},\frac{-3+-6}{2}= (2,\frac{-9}{2})$

7. anonymous

distance will be $\sqrt{(-1-5)^2+(-6-(-3))^2}=\sqrt{(-6)^2+(-3)^2}=\sqrt{36+9}=\sqrt{45}=\sqrt{9*5}=3\sqrt{5}$

8. anonymous

$\sqrt{45}=\sqrt{9*5}=3\sqrt{5}$