Suppose that a NASCAR race car is moving to the right with a constant velocity of +82 m/s. What is the average acceleration of the car? (b) Twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed. What is the average acceleration of the car?
I understand (a) but I don't understand how to solve for (b) can someone please help me?
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average acceleration = average velocity/time
= 82 / 12 = 41 / 6 = 6. 83
is my answer correct
Acceleration = dv/dt thus it is the change in velocity over the change in time or the derivative of the velocity time graph. Thus if you have a constant velocity (including both speed AND direction) then you have 0 acceleration.