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jettbalasko

  • 4 years ago

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  1. raheen
    • 4 years ago
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    6x+8y y' =0 ===> y' =-6x/8y = -3x/4y ===> y" = [-3(4y)-4y'(-3x)]/(16 y^2) = \[(3/4)y -(3x^{2}/32y^{2})\]

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