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exox

  • 4 years ago

find xintercepts and vertex of the porabola y=x^2+10x+25

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  1. raheen
    • 4 years ago
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    y=(x+5)^2 ===> vertex = (-5,0) , x-itercept is x=-5

  2. Transfiguration
    • 4 years ago
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    -5 is root and (-5,0) is the vertex. http://www.wolframalpha.com/input/?i=+y%3Dx^2%2B10x%2B25+vertex

  3. exox
    • 4 years ago
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    find the xintercepts and vertext of the porabola y=x^2+2x-24

  4. ybarrap
    • 4 years ago
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    y = (x + 1)^2+ -25 no x-intercept since vertex is at (-1,-25) http://www.wolframalpha.com/input/?i=y+%3D++%28x+%2B+1%29^2%2B+-25+vertex

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