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anonymous
 5 years ago
find xintercepts and vertex of the porabola y=x^2+10x+25
anonymous
 5 years ago
find xintercepts and vertex of the porabola y=x^2+10x+25

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=(x+5)^2 ===> vertex = (5,0) , xitercept is x=5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05 is root and (5,0) is the vertex. http://www.wolframalpha.com/input/?i=+y%3Dx^2%2B10x%2B25+vertex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find the xintercepts and vertext of the porabola y=x^2+2x24

ybarrap
 5 years ago
Best ResponseYou've already chosen the best response.0y = (x + 1)^2+ 25 no xintercept since vertex is at (1,25) http://www.wolframalpha.com/input/?i=y+%3D++%28x+%2B+1%29^2%2B+25+vertex
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