A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 4 years ago
find xintercepts and vertex of the porabola y=x^2+10x+25
anonymous
 4 years ago
find xintercepts and vertex of the porabola y=x^2+10x+25

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y=(x+5)^2 ===> vertex = (5,0) , xitercept is x=5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.05 is root and (5,0) is the vertex. http://www.wolframalpha.com/input/?i=+y%3Dx^2%2B10x%2B25+vertex

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find the xintercepts and vertext of the porabola y=x^2+2x24

ybarrap
 4 years ago
Best ResponseYou've already chosen the best response.0y = (x + 1)^2+ 25 no xintercept since vertex is at (1,25) http://www.wolframalpha.com/input/?i=y+%3D++%28x+%2B+1%29^2%2B+25+vertex
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.