Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

exox

  • 3 years ago

find xintercepts and vertex of the porabola y=x^2+10x+25

  • This Question is Closed
  1. raheen
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=(x+5)^2 ===> vertex = (-5,0) , x-itercept is x=-5

  2. Transfiguration
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -5 is root and (-5,0) is the vertex. http://www.wolframalpha.com/input/?i=+y%3Dx^2%2B10x%2B25+vertex

  3. exox
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find the xintercepts and vertext of the porabola y=x^2+2x-24

  4. ybarrap
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = (x + 1)^2+ -25 no x-intercept since vertex is at (-1,-25) http://www.wolframalpha.com/input/?i=y+%3D++%28x+%2B+1%29^2%2B+-25+vertex

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.