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Rosee
Group Title
Using quadratic formula, when do we have imaginary roots ?
 3 years ago
 3 years ago
Rosee Group Title
Using quadratic formula, when do we have imaginary roots ?
 3 years ago
 3 years ago

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prashant Group TitleBest ResponseYou've already chosen the best response.1
when your discriminant is less than zero!! D= b^2 4ac <0 then if you try to find root ....in the course you have to do sqare root(D).. as D is negative..thats why imaginary
 3 years ago

raheen Group TitleBest ResponseYou've already chosen the best response.1
\[ b^{2}4ac < 0 ===>\] there are 32 imaginary roots
 3 years ago

Japorized Group TitleBest ResponseYou've already chosen the best response.0
But I thought that when you square root a negative number, you get something undefined. Cause whatever that gets squared must be a positive number.
 3 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{25}=5i\]
 3 years ago

Japorized Group TitleBest ResponseYou've already chosen the best response.0
I know that figure but how is it defined?
 3 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[(5i)^2=25\]
 3 years ago

Japorized Group TitleBest ResponseYou've already chosen the best response.0
I mean the "i"
 3 years ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
^ tsk tsk
 3 years ago

seekevinella Group TitleBest ResponseYou've already chosen the best response.3
when b^24ac is negative or less than 0
 3 years ago

prashant Group TitleBest ResponseYou've already chosen the best response.1
whenever you have to square a negative variable like x in a equation .. must check your final answer by putting them into equation whether they satisfy or not.... because some will not satisfy...omit them from your final answer
 3 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Imaginary_number
 3 years ago

Japorized Group TitleBest ResponseYou've already chosen the best response.0
Nono. What we are finding is "Is there such a thing as imaginary roots" as we have real roots which are: \[b^{2}4ac>0\]\[b^{2}4ac=0\]\[b^{2}4ac\ge0\] So we know that \[b^{2}4ac<0\]means that it has no "real" roots. I've discussed this with my friend and we came up with the 5i idea but we don't know what it is.
 3 years ago

Japorized Group TitleBest ResponseYou've already chosen the best response.0
Sorry I was replying to Prashant. Thanks Zarkon!
 3 years ago

prashant Group TitleBest ResponseYou've already chosen the best response.1
imaginary root doesn't make any sense...although complex number is a great branch..it helps in solving a lot of problems to overcome the concept of sqroot of (1).Euler decided to take i as squareroot(1)..... i^2 =1 but in real world there is no existence of i.
 3 years ago

Japorized Group TitleBest ResponseYou've already chosen the best response.0
Of course. It's IMAGINARY. lol
 3 years ago
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