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LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
just factor
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
LAgrange!! PLEASE help.
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
the real problem is how to find the zeros of this equation and we have to explain that in steps.
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
i mean in sentences.
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
sentences
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
i dont need solutions, just HOW TO/
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
I set the function to zero Then i factored and got two terms. Next i applied the zero product property and i found the roots, by that i mean that i set each term term to zero and solved for x
 3 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
Are you sure it's 2x^3 – 9x + 3? The roots are nasty. but suppose they are r1, r2, r3, then of course 2x^3 – 9x + 3 = 2(xr1)(xr2)(xr3)
 3 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
Yes that's this. :/
 3 years ago

AnwarA Group TitleBest ResponseYou've already chosen the best response.1
You probably should try finding the roots by using some numerical methods, which will give you approximated values of the roots.
 3 years ago

AnwarA Group TitleBest ResponseYou've already chosen the best response.1
If I were you, I would start by plotting the polynomial to help me have a general view of the function and where the zeros might be. Then, I would use a method like Newton's method to approximate the roots.
 3 years ago

bookymb143 Group TitleBest ResponseYou've already chosen the best response.0
now saifoo can do this he is smart =)
 3 years ago

AnwarA Group TitleBest ResponseYou've already chosen the best response.1
I am sure he is!
 3 years ago
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