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kdsim
Math Check: Use the quadratic equation to solve: 2x^2-3x=-5 I got\frac{3\pm i \sqrt{49}}{4}\
grr\[\frac{3\pm i \sqrt{49}}{4}\ \]
2x² -3x +5 = 0 delta: (-3)² - 4*5 *2 = = 9 - 40 = -31 ~ Are you sure the equation is 2x² -3x+5 =0 not 2x²-3x-5 =0 ?
well it was 2x^2-3x=-5, that translates to 2x-3x+5-0 doesn't it? :o
so, If is 2x² -3x +5=0 delta = b² -4*a*c = -31 and \[(-b \pm \sqrt{\Delta})\div 2 *a =\] \[(-(-3)\pm \sqrt{-31}) / 4 =\] \[(3\pm i \sqrt{31} )/ 4\] \[x' = (3+ i \sqrt{31}) /4\] \[x'' = (3- i \sqrt{31}) /4\]