## marmots 3 years ago if f(x)= (3sqrtX)(X^3 -2sqrtX +6) find f'(x)

1. amistre64

do we assume X = x ?

2. marmots

yes

3. amistre64

product rule it then and youll be good

4. jrodriguez2315

Take the derivative of f'(x). Use product rule along with chain rule. f'(x)=f'(x)g(x) + f(x)g'(x).

5. marmots

I've tried that several times. I just need an answer.

6. amistre64

(3sqrtX)'(X^3 -2sqrtX +6)+(3sqrtX)(X^3 -2sqrtX +6)' $$\cfrac{3}{2\sqrt{x}}$$ (X^3 -2sqrtX +6)+ $$3\sqrt{x}\ (3x^2 -\cfrac{1}{\sqrt{x}})$$

7. amistre64

$\frac{3x^3}{2\sqrt{x}}-3+\frac{9}{\sqrt{x}}+9x^2\sqrt{x}-3$

8. jrodriguez2315

marmots make sure to regard the sqrt(x) as (x)^1/2. It makes it easier to integrate. Just a tip.

9. jrodriguez2315

I mean to take the derivative!!

10. marmots

Thanks guys, I appreciate it.

11. amistre64

yep, might need to simplify some more, but im pretty sure thats the brunt of it