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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
do we assume X = x ?
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
product rule it then and youll be good
 3 years ago

jrodriguez2315 Group TitleBest ResponseYou've already chosen the best response.1
Take the derivative of f'(x). Use product rule along with chain rule. f'(x)=f'(x)g(x) + f(x)g'(x).
 3 years ago

marmots Group TitleBest ResponseYou've already chosen the best response.0
I've tried that several times. I just need an answer.
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
(3sqrtX)'(X^3 2sqrtX +6)+(3sqrtX)(X^3 2sqrtX +6)' \(\cfrac{3}{2\sqrt{x}}\) (X^3 2sqrtX +6)+ \(3\sqrt{x}\ (3x^2 \cfrac{1}{\sqrt{x}})\)
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{3x^3}{2\sqrt{x}}3+\frac{9}{\sqrt{x}}+9x^2\sqrt{x}3\]
 3 years ago

jrodriguez2315 Group TitleBest ResponseYou've already chosen the best response.1
marmots make sure to regard the sqrt(x) as (x)^1/2. It makes it easier to integrate. Just a tip.
 3 years ago

jrodriguez2315 Group TitleBest ResponseYou've already chosen the best response.1
I mean to take the derivative!!
 3 years ago

marmots Group TitleBest ResponseYou've already chosen the best response.0
Thanks guys, I appreciate it.
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
yep, might need to simplify some more, but im pretty sure thats the brunt of it
 3 years ago
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