Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing
mr.luna
Group Title
the altitude of a triangle is increasing at a rate of 1 cm/min while the area in increasing at a rate of 2 cm^2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100cm^2?
 3 years ago
 3 years ago
mr.luna Group Title
the altitude of a triangle is increasing at a rate of 1 cm/min while the area in increasing at a rate of 2 cm^2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100cm^2?
 3 years ago
 3 years ago

This Question is Closed

shanna Group TitleBest ResponseYou've already chosen the best response.0
S= 1/2b*h dS = 1/2(h*db+b*dh) dS/dt= 1/2(h*db/dt+b*dh/dt) so 2 =1/2(10 db/dt+b*1) as S=100=1/2 b*10 b=20 so 4= 10db/dt+20 so db/dt = 1.6 cm/min (decreasing)
 3 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.