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anonymous
 5 years ago
the altitude of a triangle is increasing at a rate of 1 cm/min while the area in increasing at a rate of 2 cm^2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100cm^2?
anonymous
 5 years ago
the altitude of a triangle is increasing at a rate of 1 cm/min while the area in increasing at a rate of 2 cm^2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100cm^2?

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Hero
 5 years ago
Best ResponseYou've already chosen the best response.2What's the formula we use here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there a shorcut? i feel like i just have to double something then square it.

Hero
 5 years ago
Best ResponseYou've already chosen the best response.21. Draw diagram, include given info 2. Apply proper formula 3. Take derivative of formula 4. Input values into formula 5. Isolate what you need to find

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1317011985889:dw

Hero
 5 years ago
Best ResponseYou've already chosen the best response.2I skipped a step which is to find other necessary values

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h': 1 cm/min A': 2 cm^2/min. b'?: h=10 cm, A=100cm^2 A = bh/2 A' = b'h/2 + bh'/2 b' = (A'  bh'/2)(2/h)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0given: dA/dt= 1 dAREA/dt=2 A=10 AREA = 100

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im gona try and work it out then ill shoot you guys an answer. give me a sec

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b' = (A'  2Ah'/2h)(2/h) b' = (A'  Ah'/h)(2/h) b' = (2  100(1)/10) (2/10) b' = (2  10) (1/5) b' = 8/5 maybe?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0..... i thought this was bed :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0becasue A = bh/2; Area = base*height/2 ... solveing for base we get; base = 2*Area/height
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