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mr.luna
Group Title
the altitude of a triangle is increasing at a rate of 1 cm/min while the area in increasing at a rate of 2 cm^2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100cm^2?
 3 years ago
 3 years ago
mr.luna Group Title
the altitude of a triangle is increasing at a rate of 1 cm/min while the area in increasing at a rate of 2 cm^2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100cm^2?
 3 years ago
 3 years ago

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Hero Group TitleBest ResponseYou've already chosen the best response.2
What's the formula we use here?
 3 years ago

mr.luna Group TitleBest ResponseYou've already chosen the best response.0
is there a shorcut? i feel like i just have to double something then square it.
 3 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
1. Draw diagram, include given info 2. Apply proper formula 3. Take derivative of formula 4. Input values into formula 5. Isolate what you need to find
 3 years ago

mr.luna Group TitleBest ResponseYou've already chosen the best response.0
dw:1317011985889:dw
 3 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
I skipped a step which is to find other necessary values
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
h': 1 cm/min A': 2 cm^2/min. b'?: h=10 cm, A=100cm^2 A = bh/2 A' = b'h/2 + bh'/2 b' = (A'  bh'/2)(2/h)
 3 years ago

mr.luna Group TitleBest ResponseYou've already chosen the best response.0
given: dA/dt= 1 dAREA/dt=2 A=10 AREA = 100
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
define b as 2A/h
 3 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.2
Amistre, go to bed, lol
 3 years ago

mr.luna Group TitleBest ResponseYou've already chosen the best response.0
im gona try and work it out then ill shoot you guys an answer. give me a sec
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
b' = (A'  2Ah'/2h)(2/h) b' = (A'  Ah'/h)(2/h) b' = (2  100(1)/10) (2/10) b' = (2  10) (1/5) b' = 8/5 maybe?
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
..... i thought this was bed :)
 3 years ago

mr.luna Group TitleBest ResponseYou've already chosen the best response.0
why is b, 2A/h
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
becasue A = bh/2; Area = base*height/2 ... solveing for base we get; base = 2*Area/height
 3 years ago
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