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anonymous
 5 years ago
You are in a hotair balloon that, relative to the ground, has a velocity of 8.0 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 2.0 m/s. What are the magnitude and direction of the hawk's velocity relative to the ground? Express the directional angle relative to due east.
anonymous
 5 years ago
You are in a hotair balloon that, relative to the ground, has a velocity of 8.0 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 2.0 m/s. What are the magnitude and direction of the hawk's velocity relative to the ground? Express the directional angle relative to due east.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1317129216322:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1317129261354:dw as the awk seems to be moving due north with respect to the ballon it is stationary in the east direction with respect to the ballon and hence have a velocity 8m/s due east so magnitude of hawks velocity is the vector sum of its velocities in east and north dir = v= sqrt(8^2+2^2) v=sqrt(68) now the directional angle of velocity with east is tan^1(1/4)
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