bdboy0
how do you simplify 5(x+4)+6(x+3)
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aroub
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do you know how to distribute?
bdboy0
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no not really.... im new to all of this....
Coolsector
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5x+5*4 + 6x + 6*3 ->
11x + 38
raheen
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5x+20+6x+18=11x+38
bdboy0
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how do you distribute???
Coolsector
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for example 5*(2+3)
you multiply every term inside the bars : 5*2 + 5*3
bdboy0
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thanks i think i understand a bit bettr now. im still gonna need to keep up on studies for it
aroub
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okay,
you have 5(x+4)+6(x+3)
all you have to do is just multiply the 5 by the numbers inside the brackets like this:
5(x)+ 5(4)= 5x+20
and same thing for 6 you multiply it by everything inside the brackets
6(x) +6(3)=6x+18
now you add the numbers you got
5x+20+6x+18
11x+ 38
bdboy0
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thank you soooooooo much.... so i need help on another one first i wanna see if i get right...
aroub
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okay :)
bdboy0
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problem is 2(x-4y+1) + 3(-2x+y-2) imma try and figure out the answer first
aroub
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ok and tell me what will you get so i could check for you.. :)
bdboy0
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i think i got the first part right the second part was a lil confusing.... for the first part i got 2x-8y+2
aroub
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correct! :) , do the same thing for the second part
bdboy0
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i did but it came up as a multipplication
aroub
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ok, just tell me what did you get .. please
bdboy0
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-21
3*-6x+3y-6
aroub
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3(-2x+y-2)
3(-2x)+3(y)+3(-2)
-6x+3y-6
^ that's the true answer :)
aroub
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now add them..