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Since the equation is equal to zero, only the numerator is important.

Why only the numerator is important?

If t=0, the entire equation will equal 0, likewise, if t^2-2=0 the entire equation will equal 0.

If A/B = 0, then multiply both sides by B to get A = B*0 ---> A = 0

that's why only the numerator matters

besides, you can't divide by zero

don't I have to check for \[t^2-1 \neq 0\]?

yes it's best to find out which numbers make the denominator zero first

That would give t=1 or t=-1. Then the solution to t would t=+-sqrt(2), t=0 and t not equals +-1?

With the solution, you only need to worry about what t equals (instead of what it can't equal)

type \frac{x}{y} to type out \[\Large \frac{x}{y}\]

for some reason, this is missing in the equation editor...

Thanks!

yes that possibility exists, but you just ignore those potential solutions if it arises

Thanks everyone! :)

You're welcome.