Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

ta123 Group TitleBest ResponseYou've already chosen the best response.1
I think the answer is cos(e^(t)) e^(t)+e^(sin t)sin
 3 years ago

somesortofninja Group TitleBest ResponseYou've already chosen the best response.1
Looks like chain rule: For sin(e^t), u=e^t and du=e^t Substitute e^t with u and derive sin(u), then multiply by du: cos(u)*du Replace u & du: cos(e^t)*e^t For e^sin(t), u=sin(t) and du=cos(t) Substitute sin(t) with u and derive e^u, then multiply by du: e^u*du Replace u & du: e^sin(t)*cos(t) So you're entire answer is: \[\cos(e^t)*e^t + e^{\sin(t)}*\cos(t)\]
 3 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.