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problemsolver Group TitleBest ResponseYou've already chosen the best response.1
which?
 3 years ago

nilankshi Group TitleBest ResponseYou've already chosen the best response.1
there is nothing written..................
 3 years ago

Nancy_Lam Group TitleBest ResponseYou've already chosen the best response.0
\[\sec \theta \csc \theta=\tan \theta+\cos \theta\]
 3 years ago

jimmyrep Group TitleBest ResponseYou've already chosen the best response.0
nancy  are you sure you have got this right? i cant figure this one  so i tried plugging in 28 degrees and it didnt satisfy the identity
 3 years ago

jimmyrep Group TitleBest ResponseYou've already chosen the best response.0
r u there?
 3 years ago

mathematicalpro Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcos%28x%29 http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcot%28x%29 \[\sec \theta cosec \theta=\tan \theta+\cot \theta\] \[RHS=\tan \theta+\cot \theta\] \[=\frac{\sin \theta}{\cos \theta}+\frac{\cos \theta}{\sin \theta}\] \[=\frac{\sin^2\theta+\cos^2\theta}{\cos \theta \sin \theta}\] \[=\frac{1}{\cos \theta \sin \theta}\] \[=\sec \theta cosec \theta=LHS\]
 3 years ago
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