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anonymous
 5 years ago
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anonymous
 5 years ago
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Nilankshi
 5 years ago
Best ResponseYou've already chosen the best response.1there is nothing written..................

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sec \theta \csc \theta=\tan \theta+\cos \theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nancy  are you sure you have got this right? i cant figure this one  so i tried plugging in 28 degrees and it didnt satisfy the identity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcos%28x%29 http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcot%28x%29 \[\sec \theta cosec \theta=\tan \theta+\cot \theta\] \[RHS=\tan \theta+\cot \theta\] \[=\frac{\sin \theta}{\cos \theta}+\frac{\cos \theta}{\sin \theta}\] \[=\frac{\sin^2\theta+\cos^2\theta}{\cos \theta \sin \theta}\] \[=\frac{1}{\cos \theta \sin \theta}\] \[=\sec \theta cosec \theta=LHS\]
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