Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

problemsolver Group TitleBest ResponseYou've already chosen the best response.1
which?
 2 years ago

nilankshi Group TitleBest ResponseYou've already chosen the best response.1
there is nothing written..................
 2 years ago

Nancy_Lam Group TitleBest ResponseYou've already chosen the best response.0
\[\sec \theta \csc \theta=\tan \theta+\cos \theta\]
 2 years ago

jimmyrep Group TitleBest ResponseYou've already chosen the best response.0
nancy  are you sure you have got this right? i cant figure this one  so i tried plugging in 28 degrees and it didnt satisfy the identity
 2 years ago

jimmyrep Group TitleBest ResponseYou've already chosen the best response.0
r u there?
 2 years ago

mathematicalpro Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcos%28x%29 http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcot%28x%29 \[\sec \theta cosec \theta=\tan \theta+\cot \theta\] \[RHS=\tan \theta+\cot \theta\] \[=\frac{\sin \theta}{\cos \theta}+\frac{\cos \theta}{\sin \theta}\] \[=\frac{\sin^2\theta+\cos^2\theta}{\cos \theta \sin \theta}\] \[=\frac{1}{\cos \theta \sin \theta}\] \[=\sec \theta cosec \theta=LHS\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.