A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

nilankshi
 3 years ago
Best ResponseYou've already chosen the best response.1there is nothing written..................

Nancy_Lam
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sec \theta \csc \theta=\tan \theta+\cos \theta\]

jimmyrep
 3 years ago
Best ResponseYou've already chosen the best response.0nancy  are you sure you have got this right? i cant figure this one  so i tried plugging in 28 degrees and it didnt satisfy the identity

mathematicalpro
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcos%28x%29 http://www.wolframalpha.com/input/?i=sec%28x%29cosec%28x%29%3Dtan%28x%29%2Bcot%28x%29 \[\sec \theta cosec \theta=\tan \theta+\cot \theta\] \[RHS=\tan \theta+\cot \theta\] \[=\frac{\sin \theta}{\cos \theta}+\frac{\cos \theta}{\sin \theta}\] \[=\frac{\sin^2\theta+\cos^2\theta}{\cos \theta \sin \theta}\] \[=\frac{1}{\cos \theta \sin \theta}\] \[=\sec \theta cosec \theta=LHS\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.