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 3 years ago
Trig Identities Question: say we have sin(x+deltax) = sinx*cosdeltax + cosx*sindeltax
and we want to introduce sinx on both sides.
So, how can I put sinx on the left, and a 1 on the right like this:
sin(x+deltax)  sinx = sinx*(cosdeltax1) + cosx*sindeltax
Professor Strang is doing this in a video lecture, and I want to understand what the basis for this is. Can you help me understand this?
 3 years ago
Trig Identities Question: say we have sin(x+deltax) = sinx*cosdeltax + cosx*sindeltax and we want to introduce sinx on both sides. So, how can I put sinx on the left, and a 1 on the right like this: sin(x+deltax)  sinx = sinx*(cosdeltax1) + cosx*sindeltax Professor Strang is doing this in a video lecture, and I want to understand what the basis for this is. Can you help me understand this?

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jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0I'm going to use y instead of deltax to save time. sin(x+y) = sin(x)*cos(y) + cos(x)*sin(y) Now subtract sin(x) from both sides sin(x+y)  sin(x) = sin(x)*cos(y) + cos(x)*sin(y)  sin(x) Group like terms and factor sin(x+y)  sin(x) = (sin(x)*cos(y)  sin(x)) + cos(x)*sin(y) sin(x+y)  sin(x) = sin(x)*(cos(y)  1) + cos(x)*sin(y) Now if you want, you can replace y with deltax again to get sin(x+deltax)  sin(x) = sin(x)*(cos(deltax)  1) + cos(x)*sin(deltax)

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1you are thinking way too hard. it is not trig, it is algebra

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1what jimthompson wrote. it is not a trig identity at all

FreeTrader
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks, I seem to have lost my mind due to cos and sin being on the scene.
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