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Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object.

Physics
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1 Attachment
|F|=m|a| 51=3.8|a| 13.42=|a| In a perfect world, the angle will be 40 deg. because the object will move in the direction of the force (in real life, there are more than just this one force.
First resolve the F into its x & y components... Fx=F*cos45 Fy=F*sin45 Total forces acting on the mass becomes Ry=Fy in the y direction & Rx=40+Fx in the x direction that is the magnitude of the total force acting is \[R=\sqrt{Rx^2+Ry^2}\] at an angle \[X=\tan^{-1} (Ry/Rx)\] relative to x-axis... The direction of acceleration will be in the direction of the force (that is X itself) The magnitude of accl is R/m

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