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anonymous
 4 years ago
Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object.
anonymous
 4 years ago
Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object.

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agreene
 4 years ago
Best ResponseYou've already chosen the best response.0F=ma 51=3.8a 13.42=a In a perfect world, the angle will be 40 deg. because the object will move in the direction of the force (in real life, there are more than just this one force.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0First resolve the F into its x & y components... Fx=F*cos45 Fy=F*sin45 Total forces acting on the mass becomes Ry=Fy in the y direction & Rx=40+Fx in the x direction that is the magnitude of the total force acting is \[R=\sqrt{Rx^2+Ry^2}\] at an angle \[X=\tan^{1} (Ry/Rx)\] relative to xaxis... The direction of acceleration will be in the direction of the force (that is X itself) The magnitude of accl is R/m
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