## Aggiebound13 Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object. 2 years ago 2 years ago

First resolve the F into its x & y components... Fx=F*cos45 Fy=F*sin45 Total forces acting on the mass becomes Ry=Fy in the y direction & Rx=40+Fx in the x direction that is the magnitude of the total force acting is $R=\sqrt{Rx^2+Ry^2}$ at an angle $X=\tan^{-1} (Ry/Rx)$ relative to x-axis... The direction of acceleration will be in the direction of the force (that is X itself) The magnitude of accl is R/m