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Aggiebound13 Group Title

Only two forces act on an object (mass = 3.80 kg), as in the drawing. (F = 51.0 N.) Find the magnitude and direction (relative to the x axis) of the acceleration of the object.

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    |F|=m|a| 51=3.8|a| 13.42=|a| In a perfect world, the angle will be 40 deg. because the object will move in the direction of the force (in real life, there are more than just this one force.

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    First resolve the F into its x & y components... Fx=F*cos45 Fy=F*sin45 Total forces acting on the mass becomes Ry=Fy in the y direction & Rx=40+Fx in the x direction that is the magnitude of the total force acting is \[R=\sqrt{Rx^2+Ry^2}\] at an angle \[X=\tan^{-1} (Ry/Rx)\] relative to x-axis... The direction of acceleration will be in the direction of the force (that is X itself) The magnitude of accl is R/m

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