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max2758

  • 3 years ago

You are working in a chemistry lab. You have 1000 milliliters of pure acid. A dilution of acid is created by adding pure acid to water. A 40% dilution contains 40% acid and 60% water. You have been asked to make a 40% dilution and a 60% dilution of pure acid. a.Write an equation in standard form that models the possible quantities of each dilution you can prepare using all 1000 milliliters of pure acid. b.You prepare 700 milliliters of the 40% dilution how much of the 60% dilution can you prepare c. How much water do you need to prepare 700 milliliters of the 40% dilution?

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  1. agdgdgdgwngo
    • 3 years ago
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    \[A)\ Dilution=\frac{V_a}{V_a+V_w}\]in percent, where V_a is equal to 1000(ml) \[B)\ \ \ 0.4=\frac{V_a}{700}\] \[V_a = 280\] I have 1000-280 = 720 ml of acid left \[0.6 = \frac{720}{720+V_w}\] \[V_w = 480\] I can prepare 720+480 = 1200 milliliters of the60% dilution \[C)\ \ \ 0.4=\frac{V_a}{700} \] \[V_a = 280\] \[V_w = 700 - 280 = 420\] I need 420ml of water to prepare the 700ml 40% dilution

  2. max2758
    • 3 years ago
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    so thats the equation for part a

  3. max2758
    • 3 years ago
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    It hass tobe in standard form

  4. agdgdgdgwngo
    • 3 years ago
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    \[Dilution(V_a + V_w)=V_a\] \[Dilution*V_a + Dilution *V_w = V_a\] Where Dilution is a positive rational.

  5. max2758
    • 3 years ago
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    so does it change for all the other parts b and c

  6. agdgdgdgwngo
    • 3 years ago
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    Hmm... wait my answer isn't in standard form

  7. max2758
    • 3 years ago
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    Ya

  8. max2758
    • 3 years ago
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    Thats not in standard form Standard form is like this 2x+2y=200020202020

  9. max2758
    • 3 years ago
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    thats just an example though

  10. agdgdgdgwngo
    • 3 years ago
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    I can write it as \[V_w+(1-\frac{1}{a})*V_a=0\] which kinda matches the standard form\[Ax + By = C\]where A is 1, B is (1-1/a), and C is 0

  11. max2758
    • 3 years ago
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    Just put it in standard form like right now Ax+By=c

  12. agdgdgdgwngo
    • 3 years ago
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    It is in standard form

  13. max2758
    • 3 years ago
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    Just write it again in standard form.

  14. agdgdgdgwngo
    • 3 years ago
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    \[V_w + (1-\frac{1}{a})*V_a=0\]

  15. max2758
    • 3 years ago
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    Are you sure.

  16. agdgdgdgwngo
    • 3 years ago
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    You may substitute x for V_w, and y for V_a\[x + (1-\frac{1}{a})y=)\]

  17. agdgdgdgwngo
    • 3 years ago
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    oops:\[x+(1-\frac{1}{a})y = 0\]

  18. max2758
    • 3 years ago
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    Thanks ok i have one more question its at top can you help me with it its not as hard as this one

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