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max2758
Group Title
You are working in a chemistry lab. You have 1000 milliliters of pure acid. A dilution of acid is created by adding pure acid to water. A 40% dilution contains 40% acid and 60% water. You have been asked to make a 40% dilution and a 60% dilution of pure acid.
a.Write an equation in standard form that models the possible quantities of each dilution you can prepare using all 1000 milliliters of pure acid.
b.You prepare 700 milliliters of the 40% dilution how much of the 60% dilution can you prepare
c. How much water do you need to prepare 700 milliliters of the 40% dilution?
 3 years ago
 3 years ago
max2758 Group Title
You are working in a chemistry lab. You have 1000 milliliters of pure acid. A dilution of acid is created by adding pure acid to water. A 40% dilution contains 40% acid and 60% water. You have been asked to make a 40% dilution and a 60% dilution of pure acid. a.Write an equation in standard form that models the possible quantities of each dilution you can prepare using all 1000 milliliters of pure acid. b.You prepare 700 milliliters of the 40% dilution how much of the 60% dilution can you prepare c. How much water do you need to prepare 700 milliliters of the 40% dilution?
 3 years ago
 3 years ago

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agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
\[A)\ Dilution=\frac{V_a}{V_a+V_w}\]in percent, where V_a is equal to 1000(ml) \[B)\ \ \ 0.4=\frac{V_a}{700}\] \[V_a = 280\] I have 1000280 = 720 ml of acid left \[0.6 = \frac{720}{720+V_w}\] \[V_w = 480\] I can prepare 720+480 = 1200 milliliters of the60% dilution \[C)\ \ \ 0.4=\frac{V_a}{700} \] \[V_a = 280\] \[V_w = 700  280 = 420\] I need 420ml of water to prepare the 700ml 40% dilution
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
so thats the equation for part a
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
It hass tobe in standard form
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
\[Dilution(V_a + V_w)=V_a\] \[Dilution*V_a + Dilution *V_w = V_a\] Where Dilution is a positive rational.
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
so does it change for all the other parts b and c
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
Hmm... wait my answer isn't in standard form
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
Thats not in standard form Standard form is like this 2x+2y=200020202020
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
thats just an example though
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
I can write it as \[V_w+(1\frac{1}{a})*V_a=0\] which kinda matches the standard form\[Ax + By = C\]where A is 1, B is (11/a), and C is 0
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
Just put it in standard form like right now Ax+By=c
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
It is in standard form
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
Just write it again in standard form.
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
\[V_w + (1\frac{1}{a})*V_a=0\]
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
Are you sure.
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
You may substitute x for V_w, and y for V_a\[x + (1\frac{1}{a})y=)\]
 3 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
oops:\[x+(1\frac{1}{a})y = 0\]
 3 years ago

max2758 Group TitleBest ResponseYou've already chosen the best response.1
Thanks ok i have one more question its at top can you help me with it its not as hard as this one
 3 years ago
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