anonymous
  • anonymous
You have one cell that is 1 mm cubed, and another that is 2 mm cubed. You place both into a hypertonic solution. Which will shrivel the most? Explain and use calculations to justify the answer.
Biology
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anonymous
  • anonymous
You have one cell that is 1 mm cubed, and another that is 2 mm cubed. You place both into a hypertonic solution. Which will shrivel the most? Explain and use calculations to justify the answer.
Biology
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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TranceNova
  • TranceNova
(note: p = pi, just didn't want to re-write this in equation mode) SA/vol = 4pr^2/(4/3*p*r^3) = 4/(4/3) * 1/r = 3/r Vol=2 2=4pr^2 r=sqrt(1/(2p)) Vol=1 1=4pr^2 r=sqrt(1/p) The one with the bigger Volume will have a bigger radius and hence a smaller surface area/volume ratio (see first equation). This will mean that diffusion will occur more slowly than the smaller cell (assuming that they are sphere's) so the smaller cell will shrivel the most. Not sure if this is what your teacher will want but I hope it makes sense :)

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