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lalalyBest ResponseYou've already chosen the best response.2
f'(x)= 2x(1+x^2)^2 f''(x)= 2(1+x^2)^2 + 2x*2(1+x^2)^3 = 2(1+x^2)^2+4(1+x^2)^3
 2 years ago

lalalyBest ResponseYou've already chosen the best response.2
\[f(x)=\frac{1}{1+x^2}\] is this ur function?
 2 years ago

giggles123Best ResponseYou've already chosen the best response.1
this chick need to use parenthesis at some point.
 2 years ago

robtobeyBest ResponseYou've already chosen the best response.0
\[f[x]=\frac{1}{1+x^2} \]\[f'[x]=\frac{2 x}{\left(1+x^2\right)^2} \]\[f\text{''}[x]=\frac{8 x^2}{\left(1+x^2\right)^3}\frac{2}{\left(1+x^2\right)^2} \]\[f\text{'''}[x]=\frac{48 x^3}{\left(1+x^2\right)^4}+\frac{24 x}{\left(1+x^2\right)^3} \]
 2 years ago
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