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Cake4u

  • 4 years ago

Find F` (x) of f(x)= 1 / 1 + x^2 then calculate f`` (x)

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  1. lalaly
    • 4 years ago
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    f'(x)= -2x(1+x^2)^-2 f''(x)= -2(1+x^2)^-2 + -2x*-2(1+x^2)^-3 = -2(1+x^2)^-2+4(1+x^2)^-3

  2. lalaly
    • 4 years ago
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    \[f(x)=\frac{1}{1+x^2}\] is this ur function?

  3. giggles123
    • 4 years ago
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    this chick need to use parenthesis at some point.

  4. Cake4u
    • 4 years ago
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    yes

  5. lalaly
    • 4 years ago
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    then my answer is right

  6. Cake4u
    • 4 years ago
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    Thank you

  7. robtobey
    • 4 years ago
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    \[f[x]=\frac{1}{1+x^2} \]\[f'[x]=-\frac{2 x}{\left(1+x^2\right)^2} \]\[f\text{''}[x]=\frac{8 x^2}{\left(1+x^2\right)^3}-\frac{2}{\left(1+x^2\right)^2} \]\[f\text{'''}[x]=-\frac{48 x^3}{\left(1+x^2\right)^4}+\frac{24 x}{\left(1+x^2\right)^3} \]

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