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anonymous
 5 years ago
I know its physics but can someone help me out on this? Please...What is the resultant momentum of a system of two particles with these masses and velocities: 3.75kg m/s moving North and 4.2 kg moving Northwest at 2.3 m/s?
anonymous
 5 years ago
I know its physics but can someone help me out on this? Please...What is the resultant momentum of a system of two particles with these masses and velocities: 3.75kg m/s moving North and 4.2 kg moving Northwest at 2.3 m/s?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the 3.75kg also traveling at 3.75m/s?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait I forgot...3.75 is moving at 5.6 m/s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't totally understand the concept of the question, but it might just be that you need to add the two momentum vectors together. Step 1: draw a picturedw:1318046019675:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now calculate the momemtum vectors.dw:1318046160525:dw Now add the two vectors.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0p=mv P1=3.75*5.6=21N P2=4.2*2.3=9.66NW since its NW you know its 45degrees, so find normal vectors at that angle 9.66cos45 = 5.07 (i dont have calc) so your momentum will be 21N+5.07N = 26.07N

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i need to add the momentum together but i can't get how. I thought I have to use law of sines and cosines but I am not confident dealing with it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or you can also calculate NW vector based on your N vector and have a resulting momentum in direction of NW rather than N, however both answers should be correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To add vectors together they need to be in rectangular form, not polar form. If you have a vector in polar form as (r, theta), then its rectangular coordinates are (r cos(theta), r sin(theta)).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You said you got: In respect to the other post I used Law of Sines and Cosines and got an answer of 17.26kgm/s at 35.45 degree Nof W

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1318053871126:dw When you add vectors together, the result will be the diagonal of the parallelogram they create. So, the result has to be between the two vectors. Where is your answer vector pointing?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let P=9.66 Q=21 x=angle between the vectors which is 45 then magnitude of resultant is \[R=\sqrt{P^2+Q^2+2PQcos(x)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1318072907791:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and angle with respect to Ndirection can be obtained from: \[R\times\cos\theta=Q+P\times\cos45\]
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