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## rosy Group Title Lt (1/n)^(1/ln n)=? n->infty 3 years ago 3 years ago

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$Y=\lim_{n \rightarrow \infty} (1/n)^{1/ \ln n}$ Taking logarithm $\ln Y=\lim_{n \rightarrow \infty} (1/\ln n)\times(\ln (1/n))$ $\ln Y=\lim_{n \rightarrow \infty} (1/\ln n)\times[-\ln (n)]$ $\ln Y=\lim_{n \rightarrow \infty} (-1)$ $\ln Y=(-1)$ $Y=e^{-1}$